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charle [14.2K]
3 years ago
10

AP

Mathematics
1 answer:
enot [183]3 years ago
7 0

Answer:

x < 1 or x > 6

Step-by-step explanation:

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Sebastian wanted to order pizzas for $7 each. The delivery charge is $3.50. He has $20.
docker41 [41]

Answer:

he can buy 2

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
L = $20 r = 4% t = 2 years
Annette [7]
I'm guessing this is a question about interest rates? If you have $20 that increases by 4% in one year, you need to multiply 20 by 1.04. This gets you $20.8.

If you are talking about compound interest, we will take this number and multiply it again by 1.04 for the second year. 20.8 x 1.04 = $21.632. 

If it is instead simple interest, we will simply add another .8 dollars for each year, instead of getting 4% interest compounded every year onto the new value. This gets you $21.6.
7 0
2 years ago
Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
3 years ago
Given that the diameter of Circle A is 6 cm , and the radius of Circle B is 18 cm , what can be concluded about the two circles?
ELEN [110]

Answer:

The radius of circle B is 6 times greater than the radius of circle A

The area of circle B is 36 times greater than the area of circle A

Step-by-step explanation:

we have

<em>Circle A</em>

D=6\ cm

The radius of circle A is

r=6/2=3\ cm -----> the radius is half the diameter

<em>Circle B</em>

r=18\ cm

Compare the radius of both circles

3\ cm< 18\ cm

18=6(3)

The radius of circle B is six times greater than the radius of circle A

Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared

All circles are similar

In this problem the scale factor is 6

so

6^{2}=36

therefore

The area of circle B is 36 times greater than the area of circle A

8 0
2 years ago
Please help I will give you brainliest
mezya [45]

Answer:

Answer is 5 3/4

Step-by-step explanation:

Thanks Hope this helps

5 0
2 years ago
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