From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:
[$19.5, $22.5].
<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>
The confidence interval is given by the sample mean plus/minus the margin of error, hence:
- The lower bound is the sample mean subtracted by the margin of error.
- The upper bound is the sample mean added to the margin of error.
For this problem, we have that:
- The sample mean is of $21.
- The margin of error is of $1.50.
Hence the bounds are given as follows:
- Lower bound: 21 - 1.50 = $19.50.
- Upper bound: 21 + 1.50 = $22.50.
Hence the interval is [$19.50, $22.50].
More can be learned about confidence intervals at brainly.com/question/25890103
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Answer:
12
Step-by-step explanation:
3x^2
because the information provided states that x = -2, that is what we are going to replace x with.
3(-2)^2
the next step is to evaluate the power because that is next in PEMDAS.
(-2)^2 = 4
that leaves us with:
3 * 4 = 12 ( the " * " represents the multiplication sign)
hope this helps!
41% and 0.41 im not sure for the last one but hope im right !!
Answer:
x=2
Step-by-step explanation:
3x+2=8
<em>Subtract 2 from both sides</em>
3x=6
<em>Divide both sides by 3</em>
x=2
