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Zigmanuir [339]
3 years ago
7

Francois earns a weekly salary of$475 a5.5%commission on sales at a gift shop how much would he earn in a week if he sold $700 g

oods? Round to the nearest cent
Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

$513.50

Step-by-step explanation:

Francois earns $475 plus 5.5% or 0.055 of whatever sales he makes. If he sells $700 then he makes 0.055(700) = $38.50 in commission.

$475 + $38.50 = $513.50

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The 2nd one is right just did the test
Vikki [24]

Answer:

ok lol

Step-by-step explanation:

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3 years ago
What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of .
hjlf
The correct question is
<span>What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3
</span>
we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0

the answer is
<span>x - 3y - 7 = 0</span>
4 0
2 years ago
Read 2 more answers
If f(1) = 7 and f(n) = 5(n-1) + 2, then f(4) =
Igoryamba

Answer:

17

Step-by-step explanation:

f(n)=5(n-1)+2

f(4)=5(4-1)+2

=5×3+2

=17

hope it helps

plz. mark as brainliest

4 0
3 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
2 years ago
Next in sequence 9/16, -9/8, 9/4, -9/2, 9, ?
Fudgin [204]

Answer:

-18

Step-by-step explanation:

*2, *(-2), *2, *(-2) ...

5 0
2 years ago
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