Alex and Tory are married and filing jointly. Their gross income is

What can a person do to help increase their credit score?

never [62]

The most logical answer is D

3 0

3 years ago

Dole Company uses the periodic inventory system. At the end of the accounting period, ending inventory is $10,000 and beginnin

Troyanec [42]

Answer:

The one entry is recorded

Explanation:

The journal entry is shown below:

Inventory A/c Dr (Ending inventory) $10,000

Cost of goods sold A/c Dr (Balancing figure) $94,000

To Inventory A/c Dr (Beginning inventory) $5,000

To Purchase account $99,000

In mathematically,

Cost of goods sold = Beginning inventory + purchase - ending inventory

= $5,000 + $99,000 - $10,000

= $94,000

4 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi

Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

$\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}$

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

$1000000\sqrt{9+x^{2}$

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)$

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000$

$f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}} = 500000\\\frac{2x}{\sqrt{9+x^2}} = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\$

And we plug square root of 3 in the original cost function ad we get

$f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\$

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0

3 years ago

The Young Woman's Club of Williams has been operating for seventy-five years as an organization that supports women who stay at

likoan [24]

Answer:

A) a liability.

Explanation:

Probably, the strong culture held by the Young Woman's Club of Williams (YWCW) will be perceived to have a very low tolerance for diversity by the newcomers. It will also prevent the organization from growing in number. That doesn't mean that it will lose affiliates, but the total number of affiliates will not grow according to the growth in Williams's total population.

Since its strong culture will prevent the YWCW from growing and adapting to community changes, it should be considered a liability.

3 0

3 years ago

In a deferral adjustment for revenues collected in advance that are now earned, ______. a) the liability recorded when cash was

frosja888 [35]

Answer:

a) the liability recorded when cash was received is decreased by the adjustment for the revenue being earned

Explanation:

When cash is received for revenue yet to be earned, it is called deferred revenue. The entries posted at this point is a Debit to Cash (an increase in cash balance) and a Credit to Deferred revenue (a liability account). When the revenue gets earned, it get recognized with a Debit to Deferred revenue (to reduce the liability as the obligation has been fulfilled resulting in revenue being earned) and a Credit to Revenue (P/L).

Hence, the right option is a) the liability recorded when cash was received is decreased by the adjustment for the revenue being earned.

8 0

3 years ago