Answer:
-2, -4, -3 + 2i, -3-2i
Step-by-step explanation:
Equaling the function to zero we have:
(x ^ 2 + 6x + 8) (x ^ 2 + 6x + 13) = 0
For the first parenthesis we have:
(x ^ 2 + 6x + 8) = 0\\(x + 4) (x + 2) = 0
Therefore the roots are:
x = - 4\\x = - 2
For the second parenthesis we have:
(x ^ 2 + 6x + 13) = 0
By completing squares we have:
x ^ 2 + 6x = -13
x ^ 2 + 6x + (\frac{6}{2}) ^ 2 = -13 + (\frac{6}{2}) ^ 2\\x ^ 2 + 6x + 9 = -13 + 9\\(x + 3) ^ 2 = - 4\\x + 3 = +/- \sqrt{-4}
Therefore the roots are:
x = -3 + 2i\\x = -3 - 2i
Hope this was helpful
The answer is A. When you put it into slope-intercept form it is the only equation that turns out parallel, and when you plug in the x value 5 you get the y value of 1, which means it passes through the point (5,1)
Answer:
the area is 30 you have to muiltly the two together
Step-by-step explanation:
Let 
, so that differentiating both sides wrt 
gives
If 
and 
, the above reduces to
This is the slope of the tangent line, which has equation
The formula to find the rate of change is y2-y1/x2-x1
6-(-4)/-3-(-1)
=10/-2
=-5
