Answer:
A) $22.5
B) $12.6
C) ...
<em>Sorry but i only know two! But i hope this helps you!</em>
Answer:
sin(A+B) = 297/425
Step-by-step explanation:
This problem involves a couple of Pythagorean triples, and the trig identity for the sine of the sum of angles.
The Pythagorean triples involved are {8, 15, 17} and {7, 24, 25}. These tell us the other trig functions of the given angles:
sin(A) = 8/17 ⇔ cos(A) = 15/17
cos(B) = 24/25 ⇔ sin(B) = 7/25
The trig identity we're using is ...
sin(A+B) = sin(A)cos(B) +cos(A)sin(B)
sin(A+B) = (8/17)(24/25) +(15/17)(7/25)
![\sin(A+B)=\dfrac{8\cdot24+15\cdot 7}{17\cdot25}\\\\\boxed{\sin(A+B)=\dfrac{297}{425}}](https://tex.z-dn.net/?f=%5Csin%28A%2BB%29%3D%5Cdfrac%7B8%5Ccdot24%2B15%5Ccdot%207%7D%7B17%5Ccdot25%7D%5C%5C%5C%5C%5Cboxed%7B%5Csin%28A%2BB%29%3D%5Cdfrac%7B297%7D%7B425%7D%7D)
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<em>Check</em>
A = arcsin(8/17) ≈ 28.072°
B = arccos(24/25) ≈ 16.260°
sin(A+B) = sin(44.332°) ≈ 0.6988235
sin(A+B) = 297/425
Answer:
toss a coin three times
Step-by-step explanation:
Lower tosses means higher chance for them to all be heads, as getting heads is 50 percent. with higher tosses, it'll be more likely that you will get at least one tails