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aleksley [76]
3 years ago
9

English

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0
Dang this is too much to read i nearly understand the question
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Answer choice <br> D) A worker with 15 years of service gets 5 weeks of vacation and each year.
otez555 [7]

Answer: it seems to be D, but the equation makes practically no sense!

The value of the factor changes for the different amounts of service years and vacation weeks.

Step-by-step explanation: The equation means that the employee is trying to figure out the value of the "v-factor" for how vacation time is earned.

If you substitute the number of service years into the left side of the "formula" and vacation weeks on the right side, then solve for "v", v(15)=5 you get v= 1/3 or 0.33

If you substitute other numbers, like v(2)=2, so v= 1 then v(30) = 8, v = 4/15 or 0.2667. You see the factor's value decreases. The company is much more generous to to employees with one or two years of service than with the older ones.

7 0
3 years ago
In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
3 years ago
I need help fast in these questions.
cupoosta [38]

Answer:

all...

Step-by-step explanation:

3 0
3 years ago
The stem-and-leaf plot shows the temperatures of patients who registered at a clinic one day. How many patients registered at th
saveliy_v [14]

As the key suggests, the left part is the integer part of the number, while the digit on the right is the decimal part of the number.

So, for example, the first row describes the two values 97.2 and 97.8, while the second row describes the values 98.1, 98.3 (repeated twice), 98.5, 98.6 and 98.7 (repeater three times).

So, the number of values is given by the number of leaves: you simply have to count how many digits are there on the right part of the screen.

The answer is thus 24

5 0
3 years ago
48 m
g100num [7]

Answer:

Answer in terms of π=144π m^3

Answer by replacing π with 3.14 is 452.16 approximately 452.2m^3

Answer to the nearest whole no. is 452m^3

Step-by-step explanation:

volume \: of \: a \: cone =  \frac{1}{3} \pi {r}^{2} h

radius =  \frac{diametre}{2}

radius = 24

height = 18

slant \: height \:  = 30

first \: step

the \: exact \: volume \: of \: the \: cone \: in \: terms \: of \: \pi

v =  \frac{1}{3} \pi {r}^{2} h

\:  \:  =  \frac{1}{3}  \times \pi \times 24 \times 18

\:  \:  \:  =  \frac{432\pi}{3}

\:  \:  \:  = 144\pi

second \: step

approximate \: answer \: using \: 3.14 \: in \: place \: of \: \pi

144 \times 3.14

= 452.16

approximately \: 452.2

last \: step

answer \: to \: the \: nearest \: whole \: number

452 {m}^{3}

7 0
3 years ago
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