Question

A steel cylinder has a pressure of 550 torr at 177 degrees Celsius. What will be the pressure if the temperature is decreased by 87 degrees Celsius?

Answer 1

Answer:

$P_2=507.7torr$

Explanation:

Hello there!

In this case, when we have a gas that is undergoing a change in both pressure and temperature, we utilize the Gay-Lussac's equation as shown below:

$\frac{T_2}{P_2}=\frac{T_1}{P_1}$

Thus, since we are given the initial pressure and temperature and the final temperature, we can compute the final pressure as shown below:

$P_2=\frac{P_1}{T_1}*T_2$

So we plug in, by making sure the temperatures are in kelvins, to obtain:

$P_2=\frac{550torr}{(117+273)K}*(87+273)K\\\\P_2=507.7torr$

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