Answer:
0.501 L
Explanation:
To solve this problem we will use Boyle,s Law. According to this law "The volume of given amount of gas is inversely proportional to applied pressure at constant temperature".
V∝ 1/P
V= K/P
VP=K
Here the K is proportionality constant.
so,
P1V1 = P2V2
P= pressure
V= volume
Given data:
P1= 1 atm
V1= 461 mL
P2= 0.92 atm
V2= ? (L)
To solve this problem we have to convert the mL into L first.
1 L = 1000 mL
461/1000= 0.461 L
Now we will put the values in the equation,
P1V1 = P2V2
V2= P1V1/ P2
V2= 1 atm × 0.461 L / 0.92 atm
V2= 0.501 L
There are 3.2664292991356043 moles of MgCl2
Answer:
ΔT = 20.06 °C
Explanation:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 1.17 kJ = 1170 J
m = mass = 24.1 g
Cp = Specific Heat Capacity = 2.42 J.g⁻¹.°C⁻¹
ΔT = Change in Temperature = <u>??</u>
Solving eq. 1 for ΔT,
ΔT = Q / m Cp
Putting values,
ΔT = 1170 J / 24.1 g × 2.42 J.g⁻¹.°C⁻¹
ΔT = 20.06 °C
They are the tides and conditions of the oceans
Answer:
Option b.) Potassium ion, is written correctly.
Explanation:
Hope this helps! :)
