Answer:
Explanation:
(12 x 104 ) x (5 x 10-²) = 6 x 10 ³ 6 x 105 6.0x10²
1. (12 x 104 ) = 1248 or 1.248 x 10^3
2. (1.248 x 10^3)(5 x 10^-2) = 6.240 x 10^1 or 60 rounded to 1 sig fig
I don't understand "= 6 x 10 ³ 6 x 105 6.0x10² "
A liquid with high viscosity does not flow easily and is not effective in wetting a surface.
When a metal is subjected to corrosive elements including salt, moisture, and high temperatures, a reaction called corrosion takes place inside the metal. Some foods contain metallic compounds that can corrode a material. The majority of corrosion is simply surface dis-colouration, which polishing agents may quickly remove.
Increasing viscosity and constant intermolecular water bonding together result in surface tension. Any liquid that was more viscous than water possessed a surface tension that was equal to or lower than that of water. Viscosity with surface tension decrease when temperature rises.
Therefore, a liquid with high viscosity does not flow easily and is not effective in wetting a surface.
To know more about viscosity
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Answer:
1.55×10²² molecules.
Explanation:
We'll begin by calculating the number of mole in 5.32 g of pure lead (Pb). This can be obtained as follow:
Mass of Pb = 5.32 g
Molar mass of Pb = 207 g/mol
Mole of Pb =?
Mole = mass /molar mass
Mole of Pb = 5.32/207
Mole of Pb = 0.0257 mole
Finally, we shall determine the number of molecules in 0.0257 mole of Pb. This can be obtained as follow:
From Avogadro's hypothesis,
I mole of Pb contains 6.02×10²³ molecules.
Therefore, 0.0257 mole will contain = 0.0257 × 6.02×10²³ = 1.55×10²² molecules.
Therefore, 5.32 g of pure lead (Pb) contains 1.55×10²² molecules.
Answer:- B: 
is the right answer.
Solution:- The balanced equation is:
We have been given with 8.75 grams of oxygen and asked to calculate the grams of hydrogen needed to react with given grams of oxygen according to the balanced equation.
From balanced equation, 1 mole of oxygen reacts with 2 moles of hydrogen.
So, let's convert grams of oxygen to moles and multiply it by the mole ratio to calculate the moles of hydrogen that are easily converted to grams on multiplying by it's molar mass.
The complete set up looks as:
=
Hence, the right option is B: .
