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3 years ago

6th grade math help me pleaseee

Mathematics

2 answers:

Slav-nsk [51]3 years ago

7 0

Answer:

I think It's A and B. With you best of luck.

Step-by-step explanation:

Evgesh-ka [11]3 years ago

5 0

It is b and d. The other ones are just the same but in different words. I hope this helps you.

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30 fortyths into a decimal

lana [24]

Answer:

0.3

Step-by-step explanation:

Percent means 'per 100'. So, 30% means 30 per 100 or simply 30/100. If you divide 30 by 100, you get 0.3 (a decimal number). So, to convert from percent to decimal, simply divide by 100 and remove the '%' sign. There is a easy way to convert from percent to decimal: Just move the decimal point 2 places to the left.

Hope this helps :)

pls give brainliest :p

And let me know what you think of my pfp :0

5 0

2 years ago

a worker can complete the assembly of 15 chairs in 6 hours. At the rate,how many can the worker complete in a 40-hour work week?

san4es73 [151]

Answer:

ooo

Step-by-step explanation:

oooo

4 0

3 years ago

What is the answer to this ?

harina [27]

Answer:

The answer is option 1.

Step-by-step explanation:

In order to solve x, you have to make x the subject, by multiplying each sides by 5, to get rid of 5 on the left side.

$\frac{x}{5} = 8$

$\frac{x}{5} \times 5 = 8 \times 5$

$x = 40$

5 0

3 years ago

Nick is now seven times as old as Harry. In 6 years, Nick will be five times as old as Harry. How old will Harry be in 6 years?

Deffense [45]

Answer:

7x+6 = 5(x+6)

Step-by-step explanation:

x represents Harry's age now, so 7x represents Nick's age now. (Nick is 7 times as old as Harry.)

In 6 years, Harry's age will be x+6.

In 6 years, Nick's age will be 7x+6, which is 5 times Harry's age at that time, 5(x+6). Hence an appropriate equation is ...

... 7x+6 = 5(x+6)

_____

Please note that finding the value of x does not give the answer to the question. We are asked for Harry's age in 6 years, so the answer is x+6 (=18).

7 0

3 years ago

Read 2 more answers

Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions

monitta

I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take $z=y'$ , so that $z'=y''$ and we're left with the ODE linear in $z$ :

$y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2$

Now suppose $y$ has a power series expansion

$y=\displaystyle\sum_{n\ge0}a_nx^n$
$\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}$
$\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}$

Then the ODE can be written as

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0$

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0$

$\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0$

All the coefficients of the series vanish, and setting $x=0$ in the power series forms for $y$ and $y'$ tell us that $y(0)=a_0$ and $y'(0)=a_1$ , so we get the recurrence

$\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}$

We can solve explicitly for $a_n$ quite easily:

$a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}$

and so on. Continuing in this way we end up with

$a_n=\dfrac{a_1}{n!}$

so that the solution to the ODE is

$y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x$

We also require the solution to satisfy $y(0)=a_0$ , which we can do easily by adding and subtracting a constant as needed:

$y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}$

4 0

3 years ago