Answer:
a.No
b.No
c.No
Step-by-step explanation:
a.No,Such set does not exist .A set of natural numbers is N
Every point of this set is an isolated point but no accumulation point
Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set
Isolated point : it is defined as that point a of set S which neighborhood does not contain any other point of set except itself
Interior point of set :Let 
.Then a is called interior point of set when its neighborhood is a subset of set S.
When a set is uncountable then interior point exist it is necessary for interior points existance .
Boundary points :Let .If every non empty neighborhood of a intersect S and complement of S.
Every member of a set is a boundary point
b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers
c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of boundary point and isolated point
Just answers since long and many simplifiction
it's like doing those multiplication memory things that had like 100 questions but now with algebra fractions
5. fourth or
6. third or
7.the answe ris x+3 since it can be factored out of the 5x+15 tingie (second )
8. fourth or
9. fourth or
times
10. third or
11. second or
12. third or 11(x+7)=60
At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide
Answer:
x-2
Step-by-step explanation:
