To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
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Answer:
C. 47
Step-by-step explanation:
5(8 + 7)
Expand the brackets. Brackets mean to multiply.
5(8 + 7)
5 * 8 + 7
= 40 + 7
= 47
3(x-7x)-y
3(-6x)-y
-18x-y
