A gift card stores data using a black, magnetic stripe on the back of the card. Find the width w of the stripe.

Rufina [12.5K]

Hi there!

Let r be the number of matches that Rebecca's team won.

We know that Katheryn's team won 9 more matches than Rebecca's team, and we know that Katheryn's team won 52 matches.

Using this given information, we can create the following equation.

$r+9=52$

If you wish to solve this, we can subtract both sides by 9 to get the following value for r.

$r=43$

Have an awesome day! :)

~collinjun0827, Junior Moderator

8 0

2 years ago

Read 2 more answers

Solve ? -4-4(-x-1)=-4(6+2x)

soldier1979 [14.2K]

$-4-4(-x-1)=-4(6+2x)\\\\-4+4x+4=-24-8x\\\\4x=-24-8x \ \ /+8x\\\\12x=-24 \ \ /:12\\\\\huge\boxed{x=-2}$

7 0

2 years ago

True or False: (x + 3)2 = x2 + 9

malfutka [58]

Answer:

false

Step-by-step explanation:

3 0

3 years ago

A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes

Rudik [331]

A triangle is an example of a class of figures referred to as plane shapes. It has three straight sides and three internal angles which sum up to $180^{o}$ . The measures of the internal angles of the triangle given in the question are A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

A triangle is an example of a class of figures referred to as plane shapes. It has three straight sides and three internal angles which sum up to $180^{o}$ .

Considering the given question, let the sides of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the Cosine rule to have:

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos C

So that;

$7^{2}$ = $6^{2}$ + $(6.5)^{2}$ - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

= 29.25

Cos C = $\frac{29.25}{78}$

= 0.375

C = $Cos^{-1}$ 0.375

= 67.9757

C = $68^{o}$

Apply the Sine rule to determine the value of B,

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{6.5}{Sin B}$ = $\frac{7}{Sin 68}$

SIn B = $\frac{6.5 *Sin 68}{7}$

= 0.861

B = $Sin^{-1}$ 0.861

= 59.43

B = $59.4^{o}$

Thus to determine the value of A, we have;

A + B + C = $180^{o}$

A + $59.4^{o}$ + $68^{o}$ = $180^{o}$

A = $180^{o}$ - 127.4

= 52.6

A = $52.6^{o}$

Therefore the sizes of the internal angles of the triangle are: A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0

1 year ago

It costs $107 for 10 students and $137 for 15 students. How much does it cost for 12 students?

Anestetic [448]

$\bf \begin{array}{ccccccccc}
&&\stackrel{students}{x_1}&&\stackrel{price}{y_1}&&\stackrel{students}{x_2}&&\stackrel{price}{y_2}\\
% (a,b)
&&(~{{ 10}} &,&{{ 107}}~) 
% (c,d)
&&(~{{ 15}} &,&{{ 137}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{137-107}{15-10}\implies \cfrac{30}{5}\implies \cfrac{6}{1}\implies 6$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-107=6(x-10)
\\\\\\
y-107=6x-60
\implies 
y=6x+47\\\\
-------------------------------\\\\
\textit{how much will it be for }\stackrel{x}{12~students?}\qquad y=6(12)+47$

7 0

2 years ago