For the given quadratic equation we only have a maximum at y = 18.
<h3>
How to find the extrema of the given function?</h3>
Here we have:
Notice that this is a quadratic equation of negative leading coefficient.
Then we have a maximum at the vertex, and both arms tend to negative infinity as x tends to infinity or negative infinity.
The vertex is at:
x = -(-4)/(2*(-2)) = -1
The maximum is:
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Answer: Choice C
The equation is y = 4x-3
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How I got that answer:
The first row has x = 0 and y = -3
So the answer is narrowed to either A or C. These answer choices have a y intercept of -3. Choices B and D have a y intercept of 3.
We need the slope now. Pick any two points from the table. I'm going to pick (0,-3) and (2,5) from the first two rows.
Slope formula:
m = (y2-y1)/(x2-x1)
m = (5-(-3))/(2-0)
m = (5+3)/(2-0)
m = 8/2
m = 4
The slope is 4, so the equation is y = 4x-3
That's why the answer is choice C
(we can rule out choice A as that slope is 1)
1.d 2 could be d but I’m not sure.
The correct option is the third one.
y = -√(x - 5) + 3
<h3>Which function has a domain of x>5 and a range of y≤3?</h3>
Remember that a square root can only be evaluated in values equal or larger than zero.
So, if we want the domain to be x > 5, then we must have:
√(x - 5)
Now we also want the range to be equal or smaller than 3, then we should have a constant term equal to 3, and a negative coefficient before the square root, then we get:
y = -√(x - 5) + 3
So the correct option is the third one.
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