What is the area of the pentagon shown below a.27 square feet b. 58.5 c.85.5 d.117
1 answer:
Answer:
Option B, Area of pentagon = 58.5 Square feet
Step-by-step explanation:
The remaining part of the question is attached as image
Solution
Area of pentagon has a triangle and a trapezoid
Area of triangle = 0.5 *base *height = 0.5*9 *3 = 13.5 square feet
Area of trapezoid = Area of rectangle – 2* area of smaller triangles
= 9 ft * 6ft – ( 2 * 0.5 * 6 ft * (9 ft – 6ft) /2
= 54 – (1*6*1.5)
Area of pentagon = 13.5 + 45 = 58.5 Square feet
Hence, option B is correct
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Answer: approximately 49 feets
Step-by-step explanation:
The diagram of the tree is shown in the attached photo. The tree fell with its tip forming an angle of 36 degrees with the ground. It forms a right angle triangle,ABC. Angle C is gotten by subtracting the sum of angle A and angle B from 180(sum of angles in a triangle is 180 degrees).
To determine the height of the tree, we will apply trigonometric ratio
Tan # = opposite/ adjacent
Where # = 36 degrees
Opposite = x feets
Adjacent = 25 feets
Tan 36 = x/25
x = 25tan36
x = 25 × 0.7265
x = 18.1625
Height of the tree from the ground to the point where it broke = x = 18.1625 meters.
The entire height of the tree would be the the length of the fallen side of the tree, y + 18.1625m
To get y, we will use Pythagoras theorem
y^2 = 25^2 + 18.1625^2
y^2 = 625 + 329.88
y^2 = 954.88
y = √954.88 = 30.9 meters
Height of the tree before falling was
18.1625+30.9 = 49.0625
The height of the tree was approximately 49 feets
