Anyone know what the answer would be?
1 answer:
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Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Answer:
Step-by-step explanation:
First, find what factor each term is multiplied by to get to the next. To do this, divide the second term by the first, the third term by the second, etc
The common factor is 4. Using that, you can now write the equation for the geometric sequence in the form of:
It looks scarier than it is. aₙ is the nth term in the sequence, x is the factor, and n is the index in the sequence, that's all it is.
Plug in the information we have to get the equation for this sequence:
Then, you can solve for the 15th term:
Basically, just raise the scale factor to the power of the term you want minus 1, then multiply that by the first number.