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yan [13]
3 years ago
12

Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble

m.
Brittany is painting a mural on one of the walls in her room. The mural is in a parallelogram-shaped frame. The area of the mural is 1056 in² and the base is 32 in.

What is the height of the mural?
Mathematics
2 answers:
Anettt [7]3 years ago
8 0
A=bh
1056=32<span>×b
</span>÷32  ÷32
3<span>3=h
The height is </span>3<span>3 inches.</span>
wariber [46]3 years ago
3 0
I think the answer 33 in too and good lock with your test 
have a great day!!!
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Use the definition of the derivative as a limit to find the <br> derivative f′ where f(x)= √ x+2.
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Step-by-step explanation:

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So we get

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Multiply both equations by the conjugate.

\frac{ \sqrt{x + h + 2} -  \sqrt{x + 2}  }{h}  \times  \frac{ \sqrt{x + h + 2} +  \sqrt{x + 2}  }{ \sqrt{x + h + 2} +  \sqrt{x + 2}  }  =  \frac{x + h + 2 - (x + 2)}{h \sqrt{x +  h + 2} +  \sqrt{x + 2}  }

\frac{h}{h \sqrt{x + h + 2}  +  \sqrt{x + 2} }

\frac{1}{ \sqrt{x + h + 2}  +  \sqrt{x + 2} }

Since h is very small, get rid of h.

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\frac{ \sqrt{x + h}  -  \sqrt{x} }{h}

\frac{x + h - x}{h( \sqrt{x + h}   +  \sqrt{x}) }

\frac{h}{h( \sqrt{x + h} +  \sqrt{x} ) }

\frac{1}{ \sqrt{x + h} +  \sqrt{x}  }

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So

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