The formula used to find the area<span> of a circlular </span>sector<span> - a pie-shaped </span>part of a circle<span>. ... </span>π<span>. 4. 2. ·. 86. 360. = 12.01. What the formulae are doing is taking the </span>area<span> of the whole ... So for example, if the</span>central angle<span> was 90°, then </span>the sector<span> would </span>have<span> an </span>area<span> equal to one ... r is the </span>radius<span> of the </span>circle<span>of which </span>the sector<span> is </span>part<span>.</span>
Answer:
2.1
Step-by-step explanation:
Use the equation
Sum of elements = average x number of elements
sum = (6)(4)
sum = 24
Add up the numbers we know: 3.4 + 10.7 + 7.8 = 21.9
24 - 21.9 = 2.1
This means the fourth number is 2.1
3 (m - 2) = 2 (3m + 3) Use the Distributive Property on both sides
3m - 6 = 6m + 6 Subtract 6m from both sides
-3m - 6 = 6 Add 6 to both sides
-3m = 12 Divide both sides by -3
m = -4
Answer:
20, 4
Step-by-step explanation:
Let's assume total number of students registered is n
Last week n/4 people are absent
so people present are n - n/4 = <u>3n/4</u>
Today after return of Jen 1/5 n are absent
so people present are n - n/5 = 4n/5
which is also equal to last week present people + 1 (Jen)
= 3n/4 + 1
= (3n + 4) / 4
so (3n + 4) / 4 = 4n/5
=> 3n + 4 = 4n/5 * 4
=> (3n + 4) * 5 = 16n
=> 15n + 20 = 16n
=> 20 = n
=> n = 20
So total students registered for class is 20
today no of people absent = n/5 = 20/5 = 4
Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
