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2 years ago

I need help with number 4 if you know it

Mathematics

1 answer:

Svetradugi [14.3K]2 years ago

3 0

Answer:

the answer is 5500 but if not put 6000$

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iren [92.7K]

After plotting the data from the table, with the number of times sick per year as a function of the number of apples eaten per week, I can conclude that there is no definite correlation between the two variables. This is because the data points do not have a good fit with any trend, meaning the R-squared value is low. Thus, the number of apples eaten per week has no significant effect on the number of times the people listed get sick per year.

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2 years ago

Given log34≈1.262 and log37≈1.771, what is the value of log3(167)?

Arada [10]

Answer:

0.753

Step-by-step explanation:

I just took the test lol

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2 years ago

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Lcm of 14, 21 and 28

Zepler [3.9K]

7 is the lcm of all.

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2 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. Chris is playing a

alisha [4.7K]

Let's call the aces $h, d, c, s$ for hearts, diamonds, clubs and spades. So, $h, d$ are red and [ted] c, s[/tex] are black.

Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple

$(x,y)\, x, y \in \{h,d,c,s\}$

There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:

If we want a player to draw two card of the same colour, the following couples are good:

$(h,h),\ (h,d),\ (d,h),\ (d,d),\ (c,c),\ (c,s),\ (s,c),\ (s,s)$

so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.

Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:

$(h,c),\ (h,s),\ (d,c),\ (d,s)$

which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.

4 0

3 years ago

Read 2 more answers

Five classes collected money for a charity of their choice. The amounts of money collected by the boys and girls of each are sho

34kurt

The girls collected 8.5 pounds more than the boys in class 4

<h3>Complete question</h3>

Five classes collected money for a charity of their choice. The amounts of money collected by the boys and girls of each are shown in the chart below.

In Class 4, how much more money did the girls collect than the boys?

<h3>How to determine the difference in amounts?</h3>

From the attached chart, we have the following amount in class 4:

Girls = 12 pounds

Boys = 3.5 pounds

The difference is calculated as:

Difference = Girls - Boys

So, we have:

Difference = 12 pounds - 3.5 pounds

Evaluate

Difference = 8.5 pounds

Hence, the girls collected 8.5 pounds more than the boys in class 4