Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.
The answer is 4p i believe. (3+5p) is 8 and (1-5p) is -4, so 8p - 4p is 4p
Several examples of side lengths that are Pythagorean triples are the following with the corresponding side lengths A, B, C:
(5, 12, 13), (7, 24, 25), (3, 4, 5)
-E :)
Answer:
factoring: (
3
x
+
1
)
(
3
x+
2
)
expressing/equation: 9x²= 81x
81x + 9x + 2=
9x+81x=90x
90x + 2
Step-by-step explanation:
Answer:
20x-6
Step-by-step explanation:
