All categories

3 years ago

Abboy has 800, he spend 160. What fraction of his original money does he have left

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

Answer:

80%

Step-by-step explanation:

800-160=640

640/800=.8

.8=80%

You might be interested in

6+8x-9=11x+14-3x, can this equation be always, sometimes, or never true.

goblinko [34]

To answer the question above, simplify both sides of the equation. This gives,
8x - 3 = 8x + 14
Next, cancel the term 8x because it appears on both sides of the equation giving,
-3 = 14
That is NOT true. Therefore, the answer is the equation is NEVER TRUE.

4 0

3 years ago

Three consecutive odf integers have a sum of 39

Anestetic [448]

11, 13, 15
...............

7 0

4 years ago

Read 2 more answers

Please help! Correct answer only!

VARVARA [1.3K]

Answer:

<em>Probability ≈ 0.3571</em>

Step-by-step explanation:

Consider the steps below;

$Total Number of Outcomes - 9C4,\\9 ! / 4 ! * ( 9 - 4 ),\\9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 / 4 * 3 * 2 * 1 * 5 * 4 * 3 * 2 * 1,\\\\Total Outcomes = 126,\\\\Number of Outcomes - 3C2 * ( 6C2 ),\\3C2 = 3,\\6C2 = 15,\\\\Number of Outcomes = 3 * 15 = 45,\\\\Probability; 45 / 126 = ( About ) 0.3571$

<em>Solution; Probability ≈ 0.3571</em>

6 0

3 years ago

Convert to a mixed number: -16.04 over .2

Veseljchak [2.6K]

$\dfrac{-16.04}{0.2}=-\dfrac{16.04\cdot100}{0.2\cdot100}=-\dfrac{1604}{20}=-80\dfrac{2:2}{20:2}=-80\dfrac{1}{10}$

3 0

3 years ago

Need help with number 3 inequalities with variables on both sides

Volgvan

Answer:

x ≤ 2

Step-by-step explanation:

We are given the inequality:

$\displaystyle{2x-3 \leq \dfrac{x}{2}}$

First, get rid of the denominator by multiplying both sides by 2:

$\displaystyle{2x\cdot 2-3\cdot 2 \leq \dfrac{x}{2}\cdot 2}\\\\\displaystyle{4x-6 \leq x}$

Add both sides by 6 then subtract both sides by x:

$\displaystyle{4x-6+6 \leq x+6}\\\\\displaystyle{4x \leq x+6}\\\\\displaystyle{4x-x \leq x+6-x}\\\\\displaystyle{4x-x \leq 6}\\\\\displaystyle{3x \leq 6}$

Then divide both sides by 3:

$\displaystyle{\dfrac{3x}{3} \leq \dfrac{6}{3}}\\\\\displaystyle{x \leq 2}$

Therefore, the answer is x ≤ 2

5 0

2 years ago

Read 2 more answers