Question

Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?

Answer 1

An angle bisector divides an angle into two equal halves.

The measure of angle $\angle CPD$ is 70 degrees

The complete question is an illustrates the concept of angle bisector;

Where:

$\angle RPD = 140^o$, and line PC bisects $\angle RPD$

Because line PC bisects $\angle RPD$, then it means that the measure of RPD is twice the measure of CPD:

So, we have:

$\angle RDP = 2 \times \angle CPD$

Substitute $\angle RPD = 140^o$

$140^o = 2 \times \angle CPD$

Divide both sides by 2

$70^o = \angle CPD$

Apply symmetric property of equality:

$\angle CPD = 70^o$

Hence, the measure of angle $\angle CPD$ is 70 degrees

Read more about angle bisectors at:

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