I attached the working and the answer to the question below.
Please note that in the formula, C = speed of light, ν = frequency, λ= wavelength
<span>
The wavelength of a 2.80 Hz wave is
1.07 </span>
× 10¹⁰
cm.
Iron is iodized and Oxygen is reduced
Answer:
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
Explanation:
Let's consider the following equation.
H₂(g) + Cl₂(g) → 2 HCl(g)
We can use the balanced equation to interpret the changes in two levels: the particulate level and the molar level.
On the particulate level, we consider discrete molecules.
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level, we think in terms of moles, considering 1 mole of particles = 6.02 × 10²³ particles.
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
The average speed of the blocks are 0.36 m/s.
Explanation:
Average speed is defined as the ratio of distance covered per unit time. So if it is said that blocks are pulled to 0.9 m in the right side. This means the blocks cover a distance of 0.9 m from the origin and that distance is covered in 2.5 s. Thus, the average speed can be calculated from the change in speed with respect to time. As at time t = 0 , the speed is also zero, and at time t = 2.5 s , the speed will be
Since, in this case, the speed is equal to the average speed of blocks. So the average speed of the blocks will be 0.36 m/s.
Complete Question
The diagram of the complete question is shown on the first uploaded image.
Answer:
a) The approximate absorbance of benzoic acid at 228 nm? : A = 0.8
b) The molar absorptivity(∈)
of benzoic acid at 228 nm? : ∈ = 
Explanation:
Looking at the absorbance spectra, we can see that the approximate absorbance of benzoic acid at 228 is 0.8.
mass concentration of benzoic acid = 
the molar concentration of benzoic acid = (mass concentration of benzoic acid) / (molar mass of benzoic acid )
molar concentration of benzoic acid = 
molar concentration of benzoic acid = 
molar absorptivity (∈) of benzoic acid = (absorbance) /[ (molar concentration of benzoic acid ) × (path length) ]
∈ = (0.8) / [ (
) ×(1.00 cm)]
=
