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igor_vitrenko [27]
3 years ago
8

The following function represents the production cost f(x), in dollars, for x number of units produced by company 1: f(x) = 0.05

x2 − 7x + 300 The following table represents the production cost g(x), in dollars, for x number of units produced by company 2: x g(x) 0.6 899.58 0.8 899.52 1 899.50 1.2 899.52 1.4 899.58 Based on the given information, the minimum production cost for company _____ is greater. [Put 1 or 2 in the blank space]
Mathematics
1 answer:
Marat540 [252]3 years ago
4 0
<span>1) production cost f(x), in dollars, for x number of units produced by company 1:

f(x) = 0.05x^2 − 7x + 300

2) Table that represents the production cost g(x), in dollars, for x number of units produced by company 2:

x        g(x)
0.6     899.58

0.8     899.52

1        899.50

1.2     899.52

1.4     899.58

3) Comparison: do a table for f(x) with the same x-values of the table for g(x).

x            f(x) = </span><span>0.05x^2 − 7x + 300    g(x)

</span><span><span>0.6         295.818                               899.58

0.8         294.432                               899.52

1            293.05                                 899.50

1.2         291.672                               899.52

1.4          290.298                              899.58 </span>

As you can see the values of f(x) are consistently lower than the values of g(x) for the same x-values.

The minimum production cost for company 2 is around 899.50 at x = 1, while the minimum production cost of company 1 is defintely lower (lower than 292.298 for sure, in fact if you find the vertex it is 55).

Answer: Based on the given information, the minimum production cost for company 2 is greater. </span>


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x = (+-) sqrt 100

x = (+-) 10

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4 0
3 years ago
Pencils come in packages of 10.Erasers come in packages of 12. Phillips wants to purpose the smallest number of pencils and eras
balandron [24]

Answer:

The answer to your question is:

Packages of pencils = 6

Packages of erasers = 5

Step-by-step explanation:

Data

Pencils = 10/package

Erasers = 12 / package

Process

Find the least common factor of 10 and 12

                                    10     12     2

                                     5       6     2

                                     5       3     3

                                     5        1    5

                                      1

LCF = 2 x 2 x 3 x 5 = 60

Finally divide 60 by the number of pencils or erasers in each package

Packages of pencils = 60/10 = 6

Packages of erasers = 60/12 = 5

                                                 

5 0
3 years ago
A college parking lot is 140 ft long and 90 ft wide. The college wants to increase the area of the lot by 29% by adding strips o
Novay_Z [31]
The initial dimenssions of the park lot are:

length: 140 ft
width: 90 ft

initial area: 140 * 90 = 12,600 ft^2

Area increased 29% = 12,600 * 1.29 = 16,254 ft^2

width of the strips: x

New length: 140 + x

New width: 90 + x

New area: (140+x)(90+x) = 16,254

Solution of the equation:

12600 + 230x + x^2 = 16254

=> x^2 + 230x - 3654 = 0

Use the quadratic formula.

x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =

x = 14.92

The other solution is negative so it is discarded.

Answer: 15 ft


 
5 0
3 years ago
Length <br> Width <br><br> Pls help me
svetoff [14.1K]
These are the steps needed for this question hope this helps if there is any more questions do feel free to ask them

3 0
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