3 years ago

PLEASE HELP!!!!!!

Mathematics

1 answer:

Fofino [41]3 years ago

4 0

It is 0.088 this is just for the 20 characters so dont read this fhehfhryhfrhuehhfuyrhuyhfhefheufrhfyer

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Which is the range of the following relation?

Afina-wow [57]

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3 years ago

2v^2-12 =-12v <br> Would really appreciate it loves❤️

Black_prince [1.1K]

For this case we have the following equation:

$2v ^ 2-12 = -12v$

Rewriting we have:

$2v ^ 2 + 12v-12 = 0$

Dividing by 2 to both sides of the equation:

$v ^ 2 + 6v-6 = 0$

We apply the quadratic formula:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

We have to:

$a = 1\\b = 6\\c = -6$

Substituting:

$x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}$

Thus, we have two roots:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

ANswer:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

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3 years ago