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Alina [70]
3 years ago
8

Using only AND, OR and inverter gates to implement the above Boolean equation, how many gates are needed

Computers and Technology
1 answer:
Darina [25.2K]3 years ago
8 0

Answer: hello your question has some missing data attached below is the missing data

answer : 10 gates

Explanation:

Logic diagram Using only AND, OR and inverter gates

x = A ⊕ B ⊕ C

attached below is the require Logic diagram Using only AND, OR and inverter gates .

number of inputs > 2

number of gates needed = 10

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A small group of travelers is meeting inside an ancient building, and the travelers need access to the Internet using their mobi
artcher [175]

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c. Mobile hotspot

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3 years ago
Return a version of the given string, where for every star (*) in the string the star and the chars immediately to its left and
lana [24]

Answer:

Explanation:

The following code is written in Java and uses a for loop with a series of IF ELSE statements to check the next and previous characters in a string. Checking to make sure that there are no asterix. If so it adds that character to the String variable output. Which is returned to the user at the end of the method. Two test cases have been created and the output can be seen in the attached image below.

class Brainly {

   public static void main(String[] args) {

       System.out.println(starOut("sm*eilly"));

       System.out.println(starOut("ab**cd"));

   }

   public static String starOut(String str) {

       String output = "";

       for (int i = 0; i < str.length(); i++) {

           if ((i != 0) && (i != str.length()-1)) {

               if ((str.charAt(i-1) != '*') && (str.charAt(i+1) != '*') && (str.charAt(i) != '*')) {

                   output += str.charAt(i);

               }

           } else {

               if ((i == 0) && (str.charAt(i) != '*') && (str.charAt(i+1) != '*')) {

                   output += str.charAt(i);

               } else if ((i == str.length()-1) && (str.charAt(i) != '*') && (str.charAt(i-1) != '*')) {

                   output += str.charAt(i);

               }

           }

       }

       return output;

   }

}

4 0
3 years ago
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4 years ago
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Fiesta28 [93]

Answer:

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