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Rufina [12.5K]
4 years ago
14

The number of triangles formed in a decagon when all the diagonals from ine vertex are drawn is

Mathematics
1 answer:
masya89 [10]4 years ago
5 0
35 number of diagonal and 8 triangles
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Does anyone know the 4 answers
Naya [18.7K]
Yes, you can divide $5 by 2. There are 100 cense in a dollar, 500 in five dollars, if you divide 500 by 2 you get 250 cense, with each 100 cense equaling $1. You would have $2.50.

Also, you got number 5 wrong, it’s how far he’s gone, not how far he has left.
7 0
4 years ago
Solve the differential equation using the method of undetermined coefficients
yuradex [85]
First: the homogeneous solutions: the characteristic equation is4r^2 - 4r - 3 = 0which has roots r = 3/2, -1/2 hence the homogeneous solution isy = c1.exp(-x/2) + c2.exp(3x/2)

next you need the general form for the guess for yp and that isyp = A1cos(2x) + A2sin(2x)
Now substitute that into the equation and solve for A1, A2.
5 0
3 years ago
Describe a situation where it would be better to use a fraction than a decimal or a percentage
AysviL [449]
I prefer to use fractions for some irrational numbers.

For example, 1/3 is equal to an infinite 0.3333333333333333...
6 0
4 years ago
Read 2 more answers
How do you do this? Please give explanation
Komok [63]

Answer:

  2, 1, 3, 4, 6, 5

Step-by-step explanation:

The rate of change of function f(x) on an interval [a, b] is defined as ...

  average rate of change = (f(b) -f(a))/(b -a)

For the function h(x) = 2^-x, this will be ...

  arc = (h(b) -h(a))/(b -a) = (2^-b -2^-a)/(b-a) = (2^-a)(2^(a-b) -1)/(b -a)

__

1. For the interval [0, 2], the average rate of change is ...

  arc = (2^-0)(2^(0-2) -1)(2 -0) = (1/4 -1)/2 = -3/8 = -0.375

  1 goes in the 2nd answer blank

2-6. For the other intervals, it is convenient to let a calculator or spreadsheet compute the values. The average rates of change are shown in the attachment.

8 0
2 years ago
Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph.
Lelechka [254]

Answer:

Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)

Parallel: slopes both = -1/3

1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.

I will show the work for both the problems down below.

Step-by-step explanation:

Finding coordinates:

1+(-5)/2=-2  5+1/2=3

(-2,3)

1+4/2= 2.5   5+(-2)/2= 1.5

(2.5,1.5)

Show work verifying the EG and BC are parallel:

You can do this by finding the slope

Slop formula (y2-y1)/(x2-x1)

(1.5-3)/(2.5-(-2))

Then simplify

-1.5/2/5= -1/3 which i your slope. You use the same formula and follow thee same steps for the points of BC and both will come up as -1/4 meaning they are parallel.

Show work verifying that EG and BC are parallel:

Use distance formula to find how long each line is

√(x2-x1)^2+(y2-y1)^2

√(2.5-(-2)^2)+(1.5-3)^2

Simplify

√4.5+(1.5)=3

Do the same thing with BC and you will get 6






7 0
3 years ago
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