Two-thousand and fifty-nine
Answer:
Step-by-step explanation:
Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.
Probability for any one to be defective as of now is 
a) 
b) After I draw we have 35 good ones and 9 defective
P(F/E) =
c) P(G/EF)
This is the probability for iii bulb to be good given I and II are goog.
Once I and ii are good we have 43 bulbs with 34 good ones

Answer:
SR/BC=RT/CA And /R=/C S B And D
Step-by-step explanation:
Just Look at them then compare its pretty simple you just have to think about it.
Answer:
yes
Step-by-step explanation:
Answer:
A=z
B=-2
C=0
D=30
Step-by-step explanation:
First lets simply the equation
21 - (2x +3)2 + 4(1-1) + z^3
21 - (2x^2 + 9) + 4(0) + z ^3
21 - 2x^2 + 9 + z^3
- 2x^2 + z ^3 + 30
This means that:
A=z
B=-2
C=0
D=30