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3 years ago

How can you simplify integer expressions that contain more than one operation? answer quick pls

Mathematics

1 answer:

Lina20 [59]3 years ago

4 0

Evaluate in the order of operations! PEMDAS

Parentheses

Exponents

Multiply/Divide (left to right)

Addition/Subtraction (left to right)

Example: 5 x 2 / 5 + (6 x 3)

1. Evaluate parentheses: 6 x 3 = 18

2. Multiply and divide: 5 x 2 = 10, 10 / 5 = 2

3. Add and subtract: 2 + 18 = 20

4. We're done: 20

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Can someone please explain how to do these?

Pani-rosa [81]

Answer:

<u>First question answer:</u> The limit is 69

<u>Second question answer:</u> The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below:

$\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}$

<em>Now putting 1 in $x$ gives us the limit:</em>

$\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5$

So the answer is 5

3 0

3 years ago

-2(2n-2)>18-3n how do you solve this inequality

Svet_ta [14]

-2 * 2n -2 equals -4n + 4 > 18n -3n

8 0

3 years ago

Find the solution for x if |5x – 2| = 13.

Licemer1 [7]

Answer:

x=1 if that's 15 x

Step-by-step explanation:

4 0

3 years ago

Simplify: StartRoot StartFraction 576 Over 64 EndFraction EndRoot The prime factorization of 576 is. The prime factorization of

riadik2000 [5.3K]

The prime factor of the 576 is $2^6 * 3^2$ and the prime factor of the 64 is $2^6$ . And the expression $\sqrt{\dfrac{576}{64}}$ is equal to 3.