All categories

3 years ago

HURRY HELP 18 POINTS

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

7 0

Answer:

C. She did not follow order of operations.

Step-by-step explanation:

Order of operations says you always have to multiply before you add when solving an equation, unless there are parentheses. Meaning that she should have multiplied -9 and 2/5 first before adding -18, instead of adding -9 and -18 first.

You might be interested in

What is the value of v?<br> 1 / 4 (v – 7) = 2

belka [17]

1/4 (v - 7) = 2

1/4v - 1/4 (7/1) = 2

1/4v - 7/4 = 2

1/4v = 15/4

Multiply by 4/1 on both sides to get v

(4/1) 1/4v = 15/4 (4/1)

v = 60/4

v = 15

6 0

3 years ago

Find the area of the figure and type your result in the empty box.<br> 3 m<br> 2 m<br> 4 m

marshall27 [118]

Answer:

14m^2

Step-by-step explanation:

area of triangle = 1/2bh

= 1/2(3)(4) = 6

area of rectangle = bw

=(4)(2) = 8

6+8 = 14

8 0

3 years ago

Read 2 more answers

FIND the following. Math

podryga [215]

Answer:

Wow you needed help and nobody help, thats mean.

3 0

2 years ago

100 points!!! Pre calculus. I need helpppppppppp

Fantom [35]

Answer:

We have function,

$y = 3 - 6 \sin {}^{} (2x + \frac{\pi}{2} )$

Standard Form of Sinusoid is

$y = - 6 \sin(2x + \frac{\pi}{2} ) + 3$

Which corresponds to

$y = a \sin(b(x + c)) + d$

where a is the amplitude

2pi/b is the period

c is phase shift

d is vertical shift or midline.

In the equation equation, we must factor out 2 so we get

$y = - 6(2(x + \frac{\pi}{4} )) + 3$

Also remeber a and b is always positive

So now let answer the questions.

a. The period is

$\frac{2\pi}{ |b| }$

$\frac{2\pi}{ |2| } = \pi$

So the period is pi radians.

b. Amplitude is

$| - 6| = 6$

Amplitude is 6.

c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.

So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].

D. Plug in 0 for x.

$3 - 6 \sin((2(0) + \frac{\pi}{2} )$

$3 - 6 \sin( \frac{\pi}{2} )$

$3 - 6(1)$

$3 - 6$

$= - 3$

So the y intercept is (0,-3)

E. To find phase shift, set x-c=0 to solve for phase shift.

$x + \frac{\pi}{4} = 0$

$x = - \frac{\pi}{4}$

Negative means to the left, so the phase shift is pi/4 units to the left.

f. Period is PI, so use interval [0,2pi].

Look at the graph above,

6 0

3 years ago

Which one is right triangle angle <br>a. 45, 55 and 35<br>b. 52, 48 and 20

Gemiola [76]

<h2>option b. 52, 48 and 20</h2>

Step-by-step explanation:

<u>let's solve:-</u>

To test whether given this triangle is right triangle or not, we can use the Pythagorean Theorem .

soo

Pythagorean Theorem=

$\bold \green{(leg1)^{2} +(leg2)^{2} =(hypotenuse)^{2} }$

Here:-

$\bold \blue{leg \: 1 = 48} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bold \blue{ leg2 = 20} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bold\blue{hypotenuse = 52}$

Putting values:-

${48}^{2} + {20}^{2} = {52}^{2} \: \: \: \: \: \: \\ \\ 2304 + 400 = 2704 \\ \\ 2704 = 2704 \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

4 0

2 years ago