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3 years ago

Which statement about broadcasting a slideshow online is true?

Computers and Technology

2 answers:

9966 [12]3 years ago

4 0

Answer: PowerPoint has a free, built-in service for broadcasting online.

Explanation:

The statement that's true about the broadcast of a slideshow online is that PowerPoint has a free, built-in service for broadcasting online.

Option 1 is wrong as all transitions are not properly displayed to the audience when broadcasting online.

Option 2 is wrong as broadcasting as slideshow online is an option for most PowerPoint users.

Option 3 is wrong because when broadcasting online, third party desktop sharing software isn't necessarily an option and it isn't a must that it must be used.

Therefore, the correct option is 4.

OLEGan [10]3 years ago

4 0

Answer:

Explanation:

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Write a method called all Less that accepts two arrays of integers and returns true if each element in the first array is less t

GaryK [48]

Answer:

The program to this question can be given as:

Program:

#include<iostream> //header file

using namespace std; //using name space

bool allLess (int arr1[], int arr2[]) //defining method allLess

{

int a,b; //define variable

a= *(&arr1 + 1) - arr1; //hold length of arr1

b= *(&arr2 + 1) - arr2; //hold length of arr2

if(a!=b) //checking condition

{

return 1; //return value

}

for(int i=0; i<a; i++) //loop

{

if( arr1[i]>=arr2[i]) //checking condition

{

return 1; //return value

}

return 0; //return value

}

int main() //define main method.

{

int arr1[]={1,2,3,4,5}; //define array arr1 and assign value.

int arr2[]={4,5,6,7,8}; //define array arr2 and assign value.

cout<< allLess(arr1,arr2); //function calling

return 0;

}

Output:

Explanation:

The Explanation of the C++ language program can be given as follows:

In the above program firstly we include the header file. Then a method is defined that is "allLess" this method accepts two arrays that are "arr1 and arr2". This function returns a boolean value that is true or false.
Inside a function, we define a conditional statement and a loop in the if block we check the length of the arr1 array variable is not equal to arr2 array length. if this condition is true it will return false.
In the loop, we define another if block in this block we check that if arr1 array elements are grater then equal to arr2 array element if this condition is true it will return false. At the end of both if block and loop the function will return a value that is "true".
In the main method, we define two arrays and pass to the function and use (cout function) for print return value.

8 0

3 years ago

The security manager assigned a new security administrator the task of implementing secure protocols on all wireless access poin

Marysya12 [62]

Answer:

Good choice, as its one of the most secure wireless communications encryption methods, even though WPA2 would be the best

Explanation:

8 0

4 years ago

Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,

insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0

3 years ago

If you see these REPORT.

Alenkinab [10]

Answer:

ok will do

Explanation:

3 0

3 years ago

Read 2 more answers

Suppose that in a 00-11 knapsack problem, the order of the items when sorted by increasing weight is the same as their order whe

frosja888 [35]

Answer:

Following are the response to the given question:

Explanation:

The glamorous objective is to examine the items (as being the most valuable and "cheapest" items are chosen) while no item is selectable - in other words, the loading can be reached.

Assume that such a strategy also isn't optimum, this is that there is the set of items not including one of the selfish strategy items (say, i-th item), but instead a heavy, less valuable item j, with j > i and is optimal.

As $W_i < w_j$ , the i-th item may be substituted by the j-th item, as well as the overall load is still sustainable. Moreover, because $v_i>v_j$ and this strategy is better, our total profit has dropped. Contradiction.

8 0

3 years ago