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Mama L [17]
3 years ago
14

Please help me?

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:5 days

Step-by-step explanation:

13+3=16

16+3=19

19+3=22

22+3=25

25+3=28

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3. An acute triangle with angles measuring 60 degrees,62°, and 58 degrees,
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The owner of Darkest Tans Unlimited in a local mall is forecasting the demand for November the one new tanning booth based on th
lorasvet [3.4K]

Answer:

The forecast for November is 235 if August's forecast was 145.

Step-by-step explanation:

The formula for calculating forecast using exponential smoothing is:

F_{t} = F_{t-1}  + \alpha (A_{t-1} - F_{t-1} )

Where Ft = New month forecast

           Ft-1 = Previous month forecast

           At-1 = Previous month actual value

            α = smoothing constant

We are given F₈ = 145 (forecast for August), A₈ = 200 (Actual Value for August), α = 2, and we need to compute the forecast for November. So, We will first calculate the forecast for September then October and then November, step-by-step.

So, forecast for September is:

F₉ = F₈ + α (A₈ - F₈)

    = 145 + 2*(200-145)

    = 145 + 2*55

F₉ = 255

Then, forecast for October is:

F₁₀ = F₉ + α (A₉ - F₉)

     = 255 + 2*(220-255)

     = 255 + 2*(-35)

F₁₀ = 185

The forecast for November is:

F₁₁ = F₁₀ + α (A₁₀ - F₁₀)

    = 185 + 2*(210 - 185)

F₁₁ = 235

8 0
3 years ago
City Community College plans to increase its enrollment capacity to keep up with an increasing number of student applicants. The
aivan3 [116]
The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
                          at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now. 
                           at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students. 
3 0
3 years ago
How do you solve this
UNO [17]
7 divided by 1 is 7 so you would do long division
5 0
3 years ago
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