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2 years ago

6

if a number line plot starts from 2 (including the point) and extends towards positive infinity, the corresponding inequality is

1 answer:

murzikaleks [220]2 years ago

6 0

Answer:

$2 \leqslant y \leqslant \infty$

Step-by-step explanation:

y is equal to 2 and goes up to infinity

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Which decimal is between 6.4 and 6.6? A.) 6.04 , B.) 6.44 , C.) 6.60 , or D.) 6.06

m_a_m_a [10]

B 6.44 because 6.4 is equal to 6.40 and in between 6.40 and 6.60 there is 6.44.

4 0

2 years ago

The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(

SVEN [57.7K]

d = 3 , a₁₂ = 40 and S $x_{100}$ = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• a $n$ = a₁ + (n-1)d</h3><h3>• S $_n$ = $\frac{n}{2}$ [2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = $\frac{50}{2}$ [(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>

7 0

2 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago

Solve 2(1 – x) > 2x<br> this is my question for algebra

Rudik [331]

To solve this, you need to isolate/get the variable "x" by itself in the inequality:

2(1 - x) > 2x Divide 2 on both sides

$\frac{2(1-x)}{2} >\frac{2x}{2}$

1 - x > x Add x on both sides to get "x" on one side of the inequality

1 - x + x > x + x

1 > 2x Divide 2 on both sides to get "x" by itself

$\frac{1}{2} >x$ or $x$ (x is any number less than 1/2)

[Another way you could've solved it]

2(1 - x) > 2x Distribute 2 into (1 - x)

(2)1 + (2)(-x) > 2x

2 - 2x > 2x Add 2x on both sides

2 - 2x + 2x > 2x + 2x

2 > 4x Divide 4 on both sides to get "x" by itself

$\frac{2}{4} >\frac{4x}{4}$

$\frac{1}{2} >x$

6 0

2 years ago

Each side of a square calendar is 19 inches long. What is the calendar's perimeter?

liberstina [14]

Answer:

a square has 4 sides each of those sides is 19in long perimeter is all around the square so you would add 19+19+19+19=79in

6 0

2 years ago

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