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3 years ago

What is the volume of the right rectangular prism below?

Mathematics

1 answer:

Mice21 [21]3 years ago

8 0

Answer:

oh the only thing I can tell you is that the formula will be L x W x H sorry I'm not really good at solving fractions

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BRAINLIEST HELP ASAP!!!

Vesna [10]

2 triangles with a base of 8 and height of 6 divide the base and height in half to get the Base and height of 1 triangle and then use 1/2 B•H to find the area of one triangle 1/2 (4•3) = 6

7 0

3 years ago

0.36 as a standard form

NemiM [27]

Answer:

Step-by-step explanation:

4 0

3 years ago

What’s the answer please

skad [1K]

Answer:

h ≤ 124 / 9

h ≤ 13.78

Step-by-step explanation:

(3/4) (12h - 32) ≤ 100 (multiply both sides by 4)

(3) (12h - 32) ≤ 100 (4)

(3) (12h - 32) ≤ 400 (distribute 3 into the parenthesis)

(12h)(3) - (32)(3) ≤ 400 (expand left side terms)

36h - 96 ≤ 400 (add 96 to both sides)

36h ≤ 400 + 96

36h ≤ 496 (divide both sides by 36)

h ≤ 496 / 36 (sinmplify)

h ≤ 124 / 9

h ≤ 13.78

3 0

3 years ago

The equation of a circle is given below.

Nataliya [291]

Answer:

(h,k) = (32,-4)

r = 32

Step-by-step explanation:

The general equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$ (1)

where (h,k) is the center of the circle and r is the radius.

You have the following equation:

$x^2+(y+4)^2=64x$ (2)

You first need to complete squares in order to obtain an equation of the form (1). Thus, you have that the second term must be in a perfect square trinomial:

2b = 64

b = 32

Then, you have to sum 32^2 and also subtract the same number in the expression (2):

$x^2-64x+(y+4)^2=0\\\\(x^2-64x+32^2)+(y+4)^2-32^2=0\\\\(x-32)^2+(y+4)^2=32^2$

you compare the last result with expression (1) and obtain that the raiuds of the circle is r = 32

Furthermore, the center of the circle is (h,k) = (32,-4)

5 0

4 years ago

A store sells Brazilian coffee for $10 per lb. and Columbian coffee for $14 per lb. If the store decides to make a 150-lb. blend

Artemon [7]

Answer:

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

Step-by-step explanation:

Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.

Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

$b+c=150\\10*b+14*c=11*150$

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

$b+c=150\\10b+14c -10b-10c=11*150 -(10*150)\\4c=150\\c = 37.5$

Now, solve for b by replacing the value obtained into the first equation

$b+c=150\\b= 150 - 37.5\\b=112.5$

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

6 0

3 years ago