2 and 1/5 is your answer.
decimal form=2.2
<u>The solution to the system of equations is the</u><u> point ( -1, 9 ).</u>
What is the solution to a system of linear equations?
If you have a system of equations that contains two equations with the same two unknown variables, then the solution to that system is the ordered pair that makes both equations true at the same time.
The system of equations
y = -3x + 6 ...................(1)
y = 9 .................(2)
Substitute equation (2) in equation
9 = -3x + 6
subtract both sides
9 - 6 = -3x + 6 - 6
3 = -3x
Divide by -3 both sides
x = -1
the solution is the point ( -1, 9 )
Therefore,the solution to the system of equations is the point ( -1, 9 ).
Learn more about the solution to the system of linear equation
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<u>The complete question is -</u>
Y = –3x + 6 y = 9 what is the solution to the system of equations? (–21, 9) (9, –21) (–1, 9) (9, –1)
Answer: -3
Explanation:
This equation is called slope-intercept form the line you put in has the slope and y-intercept in it, whatever number is in front of x is the slope, this equations slope is -3.
Step-by-step explanation:
a) The rule is <em><u>multiply the previous term by 6 then add 13</u></em>. So if the 1st term is n0 = -2, then the next term n1 is
n1 = 6n0 + 13
= 6(-2) + 13
= 1
n2 = 6n1 + 13
= 6(1) + 13
= 19
So the sequence goes like
-2, 1, 19
b) Now the sequence is reversed so let's write the terms as follows:
19, 1, -2
The new rule now is <em><u>subtract</u></em><em><u> </u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>then</u></em><em><u> </u></em><em><u>divide</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>6</u></em><em><u>.</u></em> You can check this as follows:
n0 = 19
n1 = (n0 - 13)/6
= (19 - 13)/6
= 1
n2 = (n1 - 13)/6
= (1 - 13)/6
= -2
Answer:
∠G, ∠HGI, ∠IGH
Step-by-step explanation:
» <u>Concepts</u>
To name an angle, you MUST include the vertex either in the middle or have it standing by itself. To clarify, you can either call this angle ∠G, ∠HGI, or ∠IGH because they all include the vertex, G, in the middle or by itself. You put ∠HIG, which is incorrect because the vertex <u>is not </u><u>I</u>.
<u></u>
