21 and 49 GCF is 7
So then you divide 7 out of both and get 7(3m-7n)
Answer:
They got 21 wins when they have 6 losses
Step-by-step explanation:
you need to multiply 2 by whatever will get you to 6.
2*3=6
and what you do to one side you do to another side.
7*3=21
The ratio is 21:6
If you need to fill the table, you can multiply two by two and two by 4
wins | 7 | 14 | 21 | 28 |
loss | 2 | 4 | 6 | 8 |
7(2)=14
14+7=21
So the answer is 2.
Answer:
The answer is definitely C
Step-by-step explanation:
Following the system of inequalities will graph this solution best on the graph, it is the inequality represented in the graph.
ur wlcm :)
correct me if im wrong
brainliest please?
<h2>
Answer with explanation:</h2>
Let 
be the average weight of chocolate chips in each bag.
As per given , we have
Since 
is left-tailed , so we perform a left-tailed test.
Also, the population standard deviation is known 
.
So we use z-test.
Test statistic : 
Substitute given value ,
Significance level = 0.05
Decision rule : Reject 
when p-value < 0.05.
By z-table , P- value for left-tailed test = P(z<-1.96)= 1- P(z<1.96)
[∵ P(Z<-z)=1-P(Z<z)]
= 1- 0.9750
=0.025
Since , P-value(0.025) < 0.05 , so we reject the null hypothesis.
We support the claim that the machine is underfilling the bags at 0.05 significance level .
