21m-49n factored using gcf

Amber is solving this problem. 252 × 605.

expeople1 [14]

The answer would be A

6 0

3 years ago

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The exact value of cos 13pi/8 is

Naily [24]

Answer:

answer is : Cos(13pi/8) = 0.3826

Step-by-step explanation:

We have, Cos (13pi/8)

Since 13pi/8 can be shown as 3pi/2 < 13pi/8 < 2pi

Hence 13pi/8 lies on fourth quadrant.

In fourth quadrant cosine will be positive.

Cos (13pi/8) = cos(3pi/2 + pi/8)

applying formula cos(A+B) = cos A cosB - sinAsinB

i.e Cos(3pi/2 + pi/8) = cos(3pi/2)cos(pi/8) - sin(3pi/2)sin(pi/8)

∵ Remember cos(3pi/2) =0 , sin(3pi/2) = -1

Cos(3pi/2 + pi/8) = 0 cos(pi/8) - (-1)sin(pi/8)

Cos(3pi/2 + pi/8) = 0 + 0.3826

Cos(3pi/2 + pi/8) = 0.3826

Hence we got Cos(13pi/8) = 0.3826

6 0

3 years ago

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Their sum is 6 and their difference is 36<br> Help plz

Ivan

Answer:

Step-by-step explanation:

if you can use negative numbers then you could use 21 and -15

so

adding them together is 21 + (-15) = 6

and then subtracting 21 - (-15) =

21 + 15 = 36

do you think that would work ? :/

3 0

3 years ago

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Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math

bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

$p_1=X_1/n_1=82/135=0.607$

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

$p_2=X_2/n_2=41/92=0.446$

The difference between proportions is (p1-p2)=0.162.

$p_d=p_1-p_2=0.607-0.446=0.162$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=2\cdot P(z>2.4014)=0.0171$

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

$MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335$

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

6 0

3 years ago

Work out the size of angle ABC and give a reason for your answer

Mariulka [41]

Answer:

there is no picture so it is impossible to answer

Step-by-step explanation:

3 0

3 years ago