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Whitepunk [10]
3 years ago
12

Write the equation of a line that is parallel to y = -5/4x+ + 7 and that passes through the point (-4,1).

Mathematics
1 answer:
k0ka [10]3 years ago
5 0

Answer: y- 1 = -5/4(x+4)\\

Step-by-step explanation:

y = mx + b, where m is the slope, and in the equation, the slope is -5/4.

For two-line that are parallel, the slope is the same, -5/4.

y - y_{1}= m( x - x_{1})\\y- 1 = -5/4(x-(-4))\\y- 1 = -5/4(x+4)\\

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Can anyone help with this?
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3 x 2 and 1/3? The answer is 7.
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Here's the deal. I give you a question, you give me an answer. I give you points and Brainliest if possible. You use the points
olga55 [171]

Answer:

f(x) = -(x-3)^2 + 4

Step-by-step explanation:

(h; k) are the coordinates of the vertex.

On the graph are (3, 4), therefore we have:

f(x) = a(x-3)^2 + 4

We have the x- intercept (1,0) -> x=1; y=0.

Substitute them into the equation:

0 = a(1 - 3)^2 + 4

0 = a(-2)^2 + 4

4a + 4 = 0 | -4

4a = -4   |-4

a = -1

So, we have the answer:

f(x) = -(x-3)^2 + 4

5 0
3 years ago
What is the correct answer?
Tasya [4]

Given:

The function is

f(x)=(x+3)^2(x-5)^6

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}       ...(i)

where, a is a constant, c_1,c_2,...,c_n are zeros of respective multiplicities m_1,m_2,...,m_n.

We have,

f(x)=(x+3)^2(x-5)^6

On comparing this with (i), we get

c_1=-3,m_1=2

c_2=5,m_2=6

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

5 0
3 years ago
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
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