Answer:
The answers are 0, 1 and −2.
Step-by-step explanation:
Let α=arctan(2tan2x) and β=arcsin(3sin2x5+4cos2x).
sinβ2tanβ21+tan2β2tanβ21+tan2β23tanxtan2β2−(9+tan2x)tanβ2+3tanx(3tanβ2−tanx)(tanβ2tanx−3)tanβ2=3sin2x5+4cos2x=3(2tanx1+tan2x)5+4(1−tan2x1+tan2x)=3tanx9+tan2x=0=0=13tanxor3tanx
Note that x=α−12β.
tanx=tan(α−12β)=tanα−tanβ21+tanαtanβ2=2tan2x−13tanx1+2tan2x(13tanx)or2tan2x−3tanx1+2tan2x(3tanx)=tanx(6tanx−1)3+2tan3xor2tan3x−3tanx(1+6tanx)
So we have tanx=0, tan3x−3tanx+2=0 or 4tan3x+tan2x+3=0.
Solving, we have tanx=0, 1, −1 or −2.
Note that −1 should be rejected.
tanx=−1 is corresponding to tanβ2=3tanx. So tanβ2=−3, which is impossible as β∈[−π2,π2].
The answers are 0, 1 and −2.
Answer:
Answer is 5
Step-by-step explanation:
Okay hun so let me tell u what's up here
They give us this equation and ask for the 'roots'
(x+5)^3(x-9)(x+1)
Now lemme tell you the roots of this one
-5, 9, -1
you get this from making each of them 0
The answer to this would be "3" because there are 3 roots, buT wait theRe'S mOre
(x+5) goes 3 times
So thy must recount it
-5, -5, -5, 9, -1 <-- These are the roots
that's 5 roots in total
....also I did this on edgen, got it right with 5
4 fiction to 1 nonfiction
(4 x 7 = 28) fiction to (1 x 7 = 7) nonfiction
Therefore, the required ratio is 28 to 7
