1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brums [2.3K]
3 years ago
11

An electronic office product contains 5100 electronic components. Assume that the probability that each component operates witho

ut failure during the useful life of the product is 0.999, and assume that the components fail independently. Approximate the probability that 2 or more of the original 5100 components fail during the useful life of the product. Use normal approximation. Round your answer to 3 decimal places.
Mathematics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

The probability that 2 or more of the original 5,100 components may fail during the useful life of the product is:

= 0.001

Step-by-step explanation:

Probability of operating without failure = 0.999

The probability of failed component = 0.001 (1 - 0.999)

The number of components of the electronic office product = 5,100

The number of components that may fail, given the above successful operation = 5.1 (0.001 * 5,100).

Therefore, the probability that 2 or more of the original 5,100 components may fail during the useful life of the product = 0.001

Probability of component failure is the likelihood that a component fails during the useful life of the product.  It is expressed as the number of likely failed components divided by the total number of components.  This result can be left in decimal form or expressed as a percentage.

You might be interested in
What is 5+5= and 5×2​
saveliy_v [14]

Answer:

5+5=10

5x2=10

Together, they equal 20.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Add. write your answer as a mixed number in simplest form. 5 1/2+6 7/9
LiRa [457]
The answer is 12 5/18 hope it helps
7 0
3 years ago
paris run 3 1/2 laps around the circular track in the school gym. The track has a diameter of 1/2 mile. About how far does paris
fiasKO [112]

Answer:

5.497787144 miles

Step-by-step explanation:

Remember that circumference of a circle can be calculated with:

2\pi r

r=radius

We also know that the radius is just a half of the diameter.

So, the radius of the track is (1/2)/2=1/4 miles

Now, use the circumference of a circle formula to find how much she runs in 1 lap.

2\pi (\frac{1}{4} )

Simplify

\frac{\pi }{2}

This is how much she runs in 1 lap.

Multiply by 3.5 for 3 and a half laps.

\frac{\pi }{2}*3.5

The answer is around 5.497787144 miles.


7 0
3 years ago
Determine the y intercept (b) of the line 4x+2y+24=0
Rzqust [24]

Answer:

4x + 2y + 24 = 0 \\ 2y =  - 4x - 24 \\ y =  - 2x - 12 \\ { \boxed{y - intercept =  - 12}}

3 0
2 years ago
Jimmy had $4.52 to spend. He found something he wanted to buy for $6.21. How much would he need to borrow from his friend to mak
Inessa05 [86]
He would need to borrow $1.69
6 0
3 years ago
Read 2 more answers
Other questions:
  • Trevor Linden, a former player for the Vancouver Canucks, is 1.93 m tall. On a hockey card, he is 5.4 cm tall. What scale was us
    14·1 answer
  • NewPop produces their brand of soda drinks in a factory where they claim that the
    6·1 answer
  • Fishing hook E is at -7.1 feet it descends another 3.25 feet what it’s depth now
    8·1 answer
  • Need help right away
    14·1 answer
  • The product of -5 and a number is 30. What is the number ?
    10·2 answers
  • Round 80417.0858163 to the nearest hundred.
    13·2 answers
  • Rearrange the fractions in ascending order:<br> 1/3, 3/11, 6/19, 5/8
    14·1 answer
  • Write the hourly wage 15 dollars an hour as a fraction
    10·1 answer
  • write the equation of the ellipse using the given information: the ellipse has foci (0,3) and (0,-3) and major vertices (0,5) an
    8·1 answer
  • PLEASE HELP ME PLEASE<br> ITS IN THE PHOTO PLEASE<br> AND I DONT KNOW IF THATS THE ANSWER EITHER
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!