
so... notice the picture below, the angle in the fourth quadrant
now... notice, the cosine is just the distance the angle makes with the x-axis
so... using the pythagorean theorem, get the opposite side, from that triangle, keeping in mind that, "y" is negative in the 4th quadrant
once you get "y", get any other trigonometry value you need :)
Answer:
Square root of 3
Step-by-step explanation:
Look at the picture.
The point-slope form of a line:

We have the points (0, 1) and (2, 0). Substitute:

Answer: 
Answer:
A=100π=314.16 cm 2 to 5 significant figures
Step-by-step explanation: