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3 years ago

8

Five pounds of birdseed is used to fill 4 identical bird feeders. a. What fraction of the birdseed will be needed to fill each f

eeder?

2 answers:

Elis [28]3 years ago

6 0

5 divided by 4 is 5/4, so

every feeder will need 5/4 pounds of birdseed

Goryan [66]3 years ago

5 0

¼ of the five pounds for each bird feeder

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qwelly [4]

Answer:

355

Step-by-step explanation:

I think..........

4 0

3 years ago

Pls help me with this page I used all of my points

Travka [436]

Alright so the first one involves in shading.

You can see that Jack and Renee have two bars with rectangles inside the bar.

Jack took 3/4 hours or in words, three out of four. So in Jack's bar, shade 3 boxes and leave one unshaded.

Renee took 2/3 or two out of three. Shade 2 boxes in Renee's bar and see the difference.

As you can see, Jack has more shade length than Renee and that could only mean one thing:

Jack took longer to fix the tire than Renee.

The symbol that represents this is 3/4 > 2/3

The second activity has the same case.

Water: 3/5 means that you have to shade three boxes and leave the other two unshaded.

Sports Drink: 4/6 means that you have to shade four boxes and leave the other two unshaded.

As you can see again, there is more sports drink than the water since the shade length is longer in the sports drink than on the water.

This meant that she poured in more sports drink than water.

The third activity is just as simple, you just need to visually make up your own sections. Do the shading then see which one is bigger then just input the sign (hint: the first one is < and the second one is >)

cheers

7 0

3 years ago

Let h(x)=20e^kx where k ɛ R (Picture attached. Thank you so much!)

zloy xaker [14]

Answer:

A)

$k=0$

B)

$\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}$

C)

$\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}$

Step-by-step explanation:

We are given the function:

$\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}$

A)

Given that h(1) = 20, we want to find <em>k</em>.

h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

$\displaystyle (20) = 20e^{k(1)}$

Simplify:

$1= e^k$

Anything raised to zero (except for zero) is one. Therefore:

$k=0$

B)

Given that h(1) = 40, we want to find 2<em>k</em> + 1.

Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

$\displaystyle (40) = 20e^{k(1)}$

Simplify:

$\displaystyle 2 = e^{k}$

We can take the natural log of both sides:

$\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}$

By definition, ln(e) = 1. Hence:

$\displaystyle k = \ln 2$

Therefore:

$2k+1 = 2\ln 2+ 1 \approx 2.3863$

C)

Given that h(1) = 10, we want to find <em>k</em> - 3.

Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

$\displaystyle (10) = 20e^{k(1)}$

Simplfy:

$\displaystyle \frac{1}{2} = e^k$

Take the natural log of both sides:

$\displaystyle \ln \frac{1}{2} = k\ln e$

Therefore:

$\displaystyle k = \ln \frac{1}{2}$

Therefore:

$\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931$

3 0

3 years ago

All vertices must be used once in Hamilton circuits. <br><br> true<br> false

kolbaska11 [484]

Answer:

false I believe

Step-by-step explanation:

hope its right

8 0

3 years ago

Amy is 11 ⅚ years old. Camden is 1 ⅓ years younger than amy and Jane is 1 ¼ years younger than Camden How old is Jane

erastova [34]

Answer:

Jane is 9 1/4 years old

Step-by-step explanation:

Camden is 10 1/2 years old and Jane is (10 2/4 - 1 1/4) which equals 9 1/4 years

5 0

3 years ago