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Aleonysh [2.5K]
3 years ago
14

How can we get System B from System A? And are they equivalent?

Mathematics
1 answer:
Aliun [14]3 years ago
8 0
What? Where’s the question 11
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Fill in the blank to make equivalent rational expressions
artcher [175]

Answer:

-42

Step-by-step explanation:

denominator is multiplied by -7, so do the same in numerator

3 0
3 years ago
Find the area of equilateral triangle with side a.
erica [24]
A=square root of 3 over 4 times a^2
7 0
3 years ago
Read 2 more answers
If jl= 10x-2 JK = 5x-8 and KL = 7x-12 find KL
natta225 [31]
JK+KL=JL
(5x-8)+7x-12=10x-2
(add common terms together)
12x-20=10x-2
(get the term with x alone on one side of the equation)
2x=18
(divide by 2 to get x alone)
x=9

Find KL:
KL=7(9)-12
KL=51
8 0
3 years ago
Please help i am stuck and trying not to fail lol. also if you can show work pls
wel

Given:

The figure of rectangle.

To find:

a. The diagonal of the rectangle.

b. The area of the rectangle.

c. perimeter of the rectangle.

Solution:

(a)

In a right angle triangle,

\sin \theta=\dfrac{Perpendicular}{Hypotenuse}

\sin 30=\dfrac{12}{Hypotenuse}

\dfrac{1}{2}=\dfrac{12}{Hypotenuse}

Hypotenuse=12\times 2

Hypotenuse=24

So, the diagonal of the of the rectangle is 24 units.

(b)

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

\tan 30=\dfrac{12}{Base}

\dfrac{1}{\sqrt{3}}=\dfrac{12}{Base}

Base=12\sqrt{3}

Length of the rectangle is 12 and width of the rectangle is 12\sqrt{3}. So, the area of the rectangle is:

Area=length \times width

Area=12 \times 12\sqrt{3}

Area=144\sqrt{3}

So, the area of the rectangle is 144\sqrt{3} sq. units.

(c)

Perimeter of the rectangle is:

P=2(length+width)

P=2(12+12\sqrt{3})

P=24+24\sqrt{3}

P\approx 65.57

Therefore, the perimeter of the rectangle is about 65.57 units.

4 0
3 years ago
H. 7 ones 2 tenths + 4 tenths =<br> tenths =
nlexa [21]

Answer:

67

Step-by-step explanation:

7 ones are just 7, 2 tenths and 4 tenths are 20 and 40. If you add 7 + 40 + 20, you will get 67.

4 0
3 years ago
Read 2 more answers
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