Answer:
-42
Step-by-step explanation:
denominator is multiplied by -7, so do the same in numerator
A=square root of 3 over 4 times a^2
JK+KL=JL
(5x-8)+7x-12=10x-2
(add common terms together)
12x-20=10x-2
(get the term with x alone on one side of the equation)
2x=18
(divide by 2 to get x alone)
x=9
Find KL:
KL=7(9)-12
KL=51
Given:
The figure of rectangle.
To find:
a. The diagonal of the rectangle.
b. The area of the rectangle.
c. perimeter of the rectangle.
Solution:
(a)
In a right angle triangle,





So, the diagonal of the of the rectangle is 24 units.
(b)
In a right angle triangle,




Length of the rectangle is 12 and width of the rectangle is
. So, the area of the rectangle is:



So, the area of the rectangle is
sq. units.
(c)
Perimeter of the rectangle is:




Therefore, the perimeter of the rectangle is about 65.57 units.
Answer:
67
Step-by-step explanation:
7 ones are just 7, 2 tenths and 4 tenths are 20 and 40. If you add 7 + 40 + 20, you will get 67.