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Studentka2010 [4]
3 years ago
9

In a basketball game the home team scores (2m + 39) points and the visiting team scores (3m + 40) points. Find the sum to repres

ent the total points scored by the two teams m minutes past halftime.
Mathematics
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

S = (5m+79)

Step-by-step explanation:

It is given that,

Scores won by home team = (2m + 39) points

Score won by visiting team = (3m + 40) points

We need to find the sum to represent the total points scored by the two teams m minutes past halftime.

It can be calculated by the sum of score by two teams. Let the sum is S.

S = (2m + 39) + (3m + 40)

S = 5m + 79

Hence, sum to represent the total points scored by the two teams m minutes past halftime is (5m+79)

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Solving a _____ is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side length
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Read 2 more answers
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
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Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

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3 years ago
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