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dusya [7]
3 years ago
6

HURRY PLZ ANSWER 6^2+4^2

Mathematics
1 answer:
yarga [219]3 years ago
4 0

Simplify the expression.

52

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If you have an 80 average so far in class after 3 tests what would you need to get on the fourth test to have an average of 83?​
Monica [59]

Answer:

92

Step-by-step explanation:

83*4 = 332

And 80*3 = 240

332-240 = 92

So you would need 92

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I need help I’m stuck on this
arsen [322]

press ask for help i think it my help im also stumped on that

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5,3,-7,-8,-2 order from greatest to least
Burka [1]

Answer

-8, -7, -2, 3, 5

Explanation

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Negative numbers go up as they decrease.

3 0
2 years ago
Three less than the product of 18
ololo11 [35]

Answer:

(18x)-3

Step-by-step explanation:

8 0
3 years ago
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} 

2 =   e^{ \alpha t} 

 \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
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