plssss help me this is due tomorrow morning
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Using the z-distribution, it is found that the margin of error is of 0.059.
We are given the standard deviation for the population, hence the <em>z-distribution</em> is used.
<h3>What is the margin of error for a z-confidence interval?</h3>It is given by:
In which:
- z is the critical value.
is the population standard deviation.
- n is the sample size.
In this problem, the parameters are:
.
- Confidence level of 0.90, hence, using a z-distribution calculator, the critical value is z = 1.645.
Then:
The margin of error is of 0.059.
You can learn more about the z-distribution at brainly.com/question/12517818