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natali 33 [55]
3 years ago
13

plssss help me this is due tomorrow morning

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Find percent -> 2nd month.

4264*.25==1066 phone calls+=4264

==5330 for 2nd month.

for 2nd -> 3rd

6396==5330*x, solve algebraically to get .20  == 20% increase from 2nd month to 3rd month.

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The Bobcats football coach logged the following yardage gains and losses over four plays of a game.
lions [1.4K]
Answer:
9.8x - 11.1x
Explanation:
25 - 5.2 = 9.8x
0.9 - 12 = -11,1y

Notice: I’m not sure but if it wrong, you could replaced with 10x - 11y which be better answer
5 0
3 years ago
PRACTICE ANOTHER A piece of wire 18 m long is cut into two pieces. One piece is bent into a square and the other is bent into an
sergejj [24]

Answer:

Step-by-step explanation:

We have the equations

4x + 3y = 18   where x = the side of the square and y = the side of the triangle

For the areas:

A = x^2 + √3y/2* y/2

A = x^2  + √3y^2/4

From the first equation x = (18 - 3y)/4

So substituting in the area equation:

A = [ (18 - 3y)/4]^2 + √3y^2/4

A = (18 - 3y)^2 / 16 + √3y^2/4

Now for maximum / minimum area the derivative = 0 so we have

A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0

-3/8 (18 - 3y) + √3 y /2 = 0

-27/4 + 9y/8 + √3y /2 = 0

-54 + 9y + 4√3y = 0

y = 54 / 15.93

= 3.39 metres

So x = (18-3(3.39) / 4 = 1.96.

This is a minimum value for x.

So the total length of wire the square  for minimum  total area is 4 * 1.96

= 7.84 m

There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.

3 0
3 years ago
6.
saveliy_v [14]
$26.60 would be you’re answer i believe
6 0
3 years ago
Ratio of 34 inches to 1 foot
ololo11 [35]

Answer:

34:12

Step-by-step explanation:

5 0
3 years ago
what is the value of x in the diagram below? if necessary round your answer to the nearest tenth of a until
VladimirAG [237]

Answer:

C

Step-by-step explanation:

Calculate AC using Pythagoras' identity in ΔABC

AC² = 20² - 12² = 400 - 144 = 256, hence

AC = \sqrt{256} = 16

Now find AD² from ΔACD and ΔABD

ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²

ΔABD → AD² = 12² - x² = 144 - x²

Equate both equations for AD², hence

256 - 400 + 40x - x² = 144 - x²

-144 + 40x - x² = 144 - x² ( add x² to both sides )

- 144 + 40x = 144 ( add 144 to both sides )

40x = 288 ( divide both sides by 40 )

x = 7.2 → C



6 0
3 years ago
Read 2 more answers
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