All categories

3 years ago

A 20 cm

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

The answer is nearly 124 cm square

You might be interested in

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

viva [34]

Answer:

9600 m2

Step-by-step explanation:

6 0

3 years ago

A triangle and a trapezoid are graphed on the coordinate plane shown below.

Gre4nikov [31]

Answer:

10 sq units

Step-by-step explanation:

Area of triangle = 1/2(4)(2) or 4 square units

Area of trapezoid = 1/2(2)(2+4) or 6 square units

Combined area = 10 sq units

3 0

3 years ago

Simplify 12(x-4)+4(x+7)

My name is Ann [436]

Expand

12x - 48 + 4x + 28

Collect like terms

(12x + 4x) + (-48 + 28)

Simplify

16x - 20

5 0

3 years ago

Read 2 more answers

Josh has been running for 6 min and completes a lap in 7 min. Gabe has been running for 2 min and completes a lap in 9 min.

Amanda [17]

So j completed 6/7 of a lap
gabe has completed 2/9 lap
so
1 j lap=7 mins s o
7j
j=num of laps
1 g lap=9 mins so
9g
g=num of laps
then 6+j
and g+2

so
when will the times be equal
7j+6=9g+2
subtract 2 from both sides
7j+4=9g
divide both sides by 9
7/9j+4/9=g
so to get a whole number of laps, we must subsitute a number when it is multiplied by 7 then add 4, we get a multiplue of 9
so if j=2
7/9(2)+4/9=g=14/9+4/9=g=18/9=g=2
so josh and gabe must run 2 lap each because
6+(2 times 7)=2+(9 times 2)
6+14=2+18
20=20
true so

the answer is 2 laps

3 0

3 years ago

Read 2 more answers

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

3 years ago