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Korolek [52]
2 years ago
8

A 20 cm

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
7 0
The answer is nearly 124 cm square
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Given G(x) = -3/2x-9, if g(x) = -48, find x.
SpyIntel [72]

Answer:

X= 4.53

Step-by-step explanation:

You'll input g(x)= -48 into the equation then solve From there

4 0
3 years ago
|x+5| = 3<br> |x-5| = 3<br> Please help<br> NO LINKS
alexandr402 [8]

Answer:

the answer for |x+5|=3=x=-2and x=-8

and for the other one is x=8 and x=2

7 0
2 years ago
Market researchers were interested in the relationship between the price of bobbleheads and the demand of
damaskus [11]

Answer:

for each increase in prices by $1, the predicted demand decreases by 0.227 units.

Step-by-step explanation:

4 0
2 years ago
Which of the point-slope equations below are correct for the line that passes through points (-2, -2) and (2, 1)?
Ne4ueva [31]
Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4

Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)

Your final answers are:

y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
8 0
3 years ago
Lim x approaches 0 (1+2x)3/sinx
jok3333 [9.3K]

Interpreting your expression as

\dfrac{3(1+2x)}{\sin(x)}

when x approaches zero, the numerator approaches 3:

3(1+2x) \to 3(1+2\cdot 0) = 3(1+0) = 3\cdot 1 = 3

The denominator approaches 0, because \sin(0)=0

Moreover, we have

\displaystyle \lim_{x\to 0^-} \sin(x) = 0^-,\quad \displaystyle \lim_{x\to 0^+} \sin(x) = 0^+

So, the limit does not exist, because left and right limits are different:

\displaystyle \lim_{x\to 0^-} \dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^-} = -\infty,\quad \displaystyle \lim_{x\to 0^+}\dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^+} = +\infty

8 0
3 years ago
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