Answer:
0.02405 g/L is the solubility of argon in water at 25 °C.
Explanation:
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
To calculate the molar solubility, we use the equation given by Henry's law, which is:
where,
= Henry's constant = 
= partial pressure of carbonated drink = 0.51atm
Putting values in above equation, we get:
Molar mass of argon = 39.95 g/mol
Solubility of the argon gas :
0.02405 g/L is the solubility of argon in water at 25 °C.
It is based on the water underground
Answer:
The final volume will be "70.08 mL".
Explanation:
The given values are:
Molar mass,
M1 = 548 nM
or,
= 
M2 = 484 nM
or,
= 
Volume,
V1 = 61.9 mL
V1 = ?
By using the expression, we get
⇒ 
or,
⇒ 
By substituting the values, we get
An ideal gas is defined as one in which all collisions between atoms or molecules are perfectly eleastic and in which there are no intermolecular attractive forces. One can visualize it as a collection of perfectly hard spheres which collide but which otherwise do not interact with each other.
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BY CHECKING THE REACTIVITY OF AN ELEMENT WHICH IS MOST REACTIVE OR NOT AND YOU STUDY TYPE OF CHEMICAL REACTION IN 1 CH AND YOU CHECK THE REACTIVITY OF ELEMENTS IN 3 CH METALS AND NON METALS PAGE NO 45 IN NCERT BOOK
