The answer is D: Salt and Water
5N force was applied to an object if 35 j of work was done and the object moved 7 m
A force is an effect that can alter an object motion according to physics and an object with mass can change its velocity or accelerate as a result force and also force is as push or pull and work done by the force on an object means assuming that direction of the force is parallel to the displacement of the object
Then the formula is
W = f × d
Where f is the magnitude of force and d is the displacement of the object
Then W = 35 J is the work done and
d = 7m is the displacement of the object
So rearrange the equation then
F = 35/7 = 5N
5N force was applied to an object if 35 j of work was done and the object moved 7 m
Know more about object
brainly.com/question/11748734
#SPJ9
20.7 Degree celsius is the temperature of Zippy's room.
Explanation:
The initial conditions of the kookie cola will be depicted by P1,V1 and T1.
P1= 36.5 psi or 2.4816 atm
V1= 355ml or 0.35 L
T1= 275.5K
The final conditions are given P2,V2 and T2
P2= 38.9 psi or 2.6469 atm
V2 = 355 ml or 0.35 L
also the solubility of the carbon dioxide does not change with temperature.
Applying the formula
P1VI/T1=P2V2/T2
since volume does not change and remains constant.
It can be written as:
P1/T1=P2/T2
= 2.4816/275.5=2.6469/T2
T2= 293.85 K
Answer:
21.344%
Explanation:
For the given chemical reaction, 8 moles of the reactant should produce 4 moles of 
. However, 195 g of was produced instead. The molar mass of is 61.9789 g/mol.
Thus, the moles of produced = 195/61.9789 = 3.1462 moles
The percent error = [(Actual -Experiment)/Actual]*100%
The percent error = [(4.00 - 3.1462)/4.00]*100% = (0.85376/4.00)*100% = 21.344%
Answer:
The mass of radon that decompose = 63. 4 g
Explanation:
R.R = P.E/(2ᵇ/ⁿ)
Where R.R = radioactive remain, P.E = parent element, b = Time, n = half life.
Where P.E = 100 g , b = 5.55 days, n = 3.823 days.
∴ R.R = 100/
R.R = 100/
R.R = 100/2.73
R.R = 36.63 g.
The mass of radon that decompose = Initial mass of radon - Remaining mass of radon after radioactivity.
Mass of radon that decompose = 100 - 36.63
= 63.37 ≈ 63.4 g
The mass of radon that decompose = 63. 4 g
