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kiruha [24]
3 years ago
11

Which of these are true for the reaction above?

Chemistry
1 answer:
agasfer [191]3 years ago
6 0

Answer:

a, d, f

Explanation:

ΔHrxn = ΔH(CCl4) -ΔH(CH4) = - 106.7 -(-74.8) = - 31.9 kJ/mol

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In calculating the change in enthalpy in a certain reaction, it is important to remember that it is the sum of the enthapy of formation for the substances involved in the reaction. 

<span>CaO(s)+2HCl(aq)→CaCl2(aq)+H2O(l)                          ΔH= –186kJ 
</span>Ca(OH)2(aq) →  CaO(s)+H2O(l)<span>                                     ΔH= 65.1 kJ
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3 years ago
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