Answer:
tangent theta = 12/5,
cosecant theta = 13/12
secant theta = 13/5
Cotangent theta = 5/12
Step-by-step explanation:
Given sine theta= 12/13, cosine theta= 5/13.
According to SOH CAH TOA
Sintheta = Opposite/Hypotenuse = 12/13
Cosine theta = Adjacent/Hypotenuse = 5/13
Opposite = 12, Adjacent = 5, Hypotenuse = 13
Tan theta = Opposite/Adjacent = 12/5.
cosecant theta = 1/sintheta = 1/{12/13}
cosecant theta = 13/12
secant theta = 1/cos theta = 1/{5/13}
Secant theta = 13/5.
Cotangent theta = 1/tan theta = 1/{12/5} = 5/12
Answer:
1. k=0
2. yes, result is still a polynomial.
3. yes, f and g must have the same degree to have deg(f+g) < deg(f) or deg(g)
Step-by-step explanation:
1. for what constant k must f(k) always equal the constant term of f(x) for any polynomial f(x)
for k=0 any polynomial f(x) will reduce f(k) to the constant term.
2. If we multiply a polynomial by a constant, is the result a polynomial?
Yes, If we multiply a polynomial by a constant, the result is always a polynomial.
3. if deg(f+g) is less than both deg f and deg g, then must f and g have the same degree?
Yes.
If
deg(f+g) < deg(f) and
deg(f+g) < deg(g)
then it means that the two leading terms cancel out, which can happen only if f and g have the same degree.
Answer:
8
Step-by-step explanation:
To solve this, you can add 2/5 b to both sides of the equation. You now have 3 + 5/5 (or 1) b = 11. => 3 + b = 11 => Now, subtract 3 from both sides, and you have b = 11 - 3, and then b = 8.
Answer:
Hey Friend.....
Step-by-step explanation:
This is ur answer....
<h3>
<em>68 + 52 = 120</em></h3><h3>
<em>Sum of Triangle = 180 </em></h3><h3>
<em>Value of Interior Angle = </em></h3><h3>
<em>180 - 120 </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>= 60</em></h3><h3>
<em>Supplementary Angle Measure </em><em>=</em><em> </em><em>180 </em></h3><h3>
<em>= 180 - 60 </em></h3><h3>
<em> </em></h3><h3>
<em>Value of F Angle = 120</em></h3>
Hope it helps!
Brainliest pls!
Follow me! :)