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Varvara68 [4.7K]

3 years ago

10

Samantha gets paid $4,000 each month. She spends a total of $3,700 on housing, food, transportation, and phone bills. If Samanth

a wants to buy a new laptop for $1,200, how many months will she have to save up for it?*
A. 1 month
B.3 months
C.4 months
D.I don't know

2 answers:

ivann1987 [24]3 years ago

8 0

I believe the answer is c

Nadya [2.5K]3 years ago

7 0

Answer:

C. 4 months

Step-by-step explanation:

4000-3700= 300 leftover every month

1200/300=4

after 4 months she will have $1,200

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Alana praticed dancing for 11 over 4 hours on Monday, 19 over 8 hours on Wednesday, and 2.6 hours on Friday. On which day did sh

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On Friday because if she danced 11 - negative 4 = 15. and 19 - negative 8=27. the closest would be Friday because on that day she danced for 2.6 hours.

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4 years ago

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A string running from the ground to the top of a fence has an angle of elevation of 45°. The string is 10 feet long. What is the

Elza [17]

Answer: The distance between the fence and where the string is pegged to the ground is 7.07 feet.

Step-by-step explanation:

Since we have given that

Length of string = 10 feet

Angle of elevation = 45°

We need to find the distance between the fence and where the string is pegged to the ground.

We will apply "Cosine formula "

$\cos 45^\circ=\dfrac{Base}{Hypotenuse}\\\\\dfrac{1}{\sqrt{2}}=\dfrac{Base}{10}\\\\Base=\dfrac{10}{\sqrt{2}}\\\\Base=7.07\ feet$

Hence, the distance between the fence and where the string is pegged to the ground is 7.07 feet.

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3 years ago

Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round

Karo-lina-s [1.5K]

Answer:

1. D. $50\text{ units}^2$

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of base line of our triangle we will get,

$\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}$

$\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}$

$\text{Base length of triangle}=\sqrt{100+100}$

$\text{Base length of triangle}=\sqrt{200}$

$\text{Base length of triangle}=10\sqrt{2}$

Now let us find the height of triangle similarly.

$\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}$

$\text{Height of triangle}=\sqrt{(5)^2+(5)^2}$

$\text{Height of triangle}=\sqrt{25+25}$

$\text{Height of triangle}=\sqrt{50}$

$\text{Height of triangle}=5\sqrt{2}$

$\text{Area of triangle}=\frac{\text{Base*Height}}{2}$

$\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}$

$\text{Area of triangle}=\frac{50*2}{2}$

$\text{Area of triangle}=50$

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

$\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}$

$\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}$

$\text{Large side of rectangle}=\sqrt{169+169}$

$\text{Large side of rectangle}=\sqrt{338}$

$\text{Large side of rectangle}=13\sqrt{2}$

$\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}$

$\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}$

$\text{Small side of rectangle}=\sqrt{9+9}$

$\text{Small side of rectangle}=\sqrt{18}$

$\text{Small side of rectangle}=3\sqrt{2}$

$\text{Perimeter of rectangle}=2(\text{Length + Width)}$

$\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}$

$\text{Perimeter of rectangle}=2(16\sqrt{2}}$

$\text{Perimeter of rectangle}=32\sqrt{2}$

$\text{Perimeter of rectangle}=45.2548339959390416\approx 45$

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

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4 years ago

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borishaifa [10]

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Make a chart for this sort of problem it makes it easier. Excel is good for it

5 0

3 years ago

Quick and easy geometry thanks please help !!!!!

netineya [11]

Answer:

Midpoint of segment AB= (-0.5, 0)

Step-by-step explanation:

The midpoint coordinates of the midpoint has the x coordinate on .5 and the y coordinate on 0.

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4 years ago