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Irina18 [472]
3 years ago
5

Please help me with this question. Thank you :)

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0
80°...................
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A mountain climber descends 3,852 feet over a period of 4 days. What was the average amount of her descent over that period of t
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To get the answer, divide 3852 feet by 4 days. That will give you an average of 963 feet per day as your answer.
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Answer:

15 ,90 30 45.90,23,23,45,

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Step-by-step explanation:

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4+ (-7) is. Blank units from 4, in the Direction what will the answer be ? I also
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4+​(−​7)  is​ 7 units from​ 4, in the​ negative direction​ (that is, to the left of 4)

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A rectangle has a length of x inches and a width 2 inches less than the length. If the dimensions were tripled what would be the
vagabundo [1.1K]
Originally we have
length = x
width = x-2
since the width is 2 inches smaller than the length

now let's triple each dimension. Multiply the expressions by 3 to get
new length = 3*x
new width = 3*(x-2) = 3x-6

Now onto the area
area = (length)*(width)
area = (3x)*(3x-6)
area = 3x*3x-3x*6
area = 9x^2 - 18x

So the new larger rectangle has area of 9x^2-18x
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3 years ago
Find the sum of the arithmetic sequence. 3,5,7,9,....,21
inysia [295]
The sum of any arithmetic sequence is the average of the first and last terms times the number of terms.

Any term in an arithmetic sequence is:

a(n)=a+d(n-1), where a=initial term, d=common difference, n=term number

So the first term is a, and the last term is a+d(n-1) so the sum can be expressed as:

s(n)(a+a+d(n-1))(n/2)

s(n)=(2a+dn-d)(n/2)

s(n)=(2an+dn^2-dn)/2

However we need to know how many terms are in the sequence.

a(n)=a+d(n-1), and we know a=3 and d=2 and a(n)=21 so

21=3+2(n-1)

18=2(n-1)

9=n-1

10=n so there are 10 terms in the sequence.

s(n)=(2an+dn^2-dn)/2, becomes, a=3, d=2, n=10

s(10)=(2*3*10+2*10^2-2*10)/2

s(10)=(60+200-20)/2

s(10)=240/2

s(10)=120
7 0
3 years ago
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