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k0ka [10]
2 years ago
9

Can somebody please help

Mathematics
1 answer:
quester [9]2 years ago
8 0

Answer:

Every equation has a solution.

Hope that helps!?

Step-by-step explanation:

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Which compound inequality is graphed?
jek_recluse [69]
The answer is D hope this helps!!
5 0
2 years ago
50 PTS<br> Please Make sure its easy to understand
kkurt [141]

Answer:

1) -95.

2) 15.

3) The conference center is on floor 5.

Step-by-step explanation:

1) Evaluating gives -52-30-13=-(52+30+13)=-(95)=-95.

2) Substituting gives x+27=(-12)+27=15.

3) After going 4 floors down, we are on level -4. After going 9 floors up to the desired room, we are on level -4+9=5. So the conference center is on floor 5.

3 0
3 years ago
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Hello can anyone help me ? here the question
lesantik [10]

Answer:

A. 1/5k - 2/3j and -2/3j +1/5k

Step-by-step explanation:

A. 1/5k - 2/3j and -2/3j +1/5k

B. 1/5k - 2/3j and -1/5k +2/3j

There is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

Not equivalent

C. 1/5k - 2/3j and 1/5j - 2/3k

There is a change in the variables

1/5k changed to 1/5j

-2/3j changed to -2/3k

D. 1/5k - 2/3j and 2/3j - 1/5k

The is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

The only equivalent expression is

A. 1/5k - 2/3j and -2/3j +1/5k

3 0
3 years ago
Pls help i beg i will give brainlist and points
leonid [27]

Answer:

7. 1/10 or 10%

9.5/10

11.5/10

13.9/10

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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miskamm [114]

Answer:

a) he rate of change of the volume of a snowball (due to melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3

\frac{dV(t)}{dT} = A*V(t)^{2} \\ and V(0) = 900cm^{3}

where A is a real constant, it appears because it says that the change i volume (dV/dt) is "proportional" to V(t)^{2}. Furthermore, we should assume that A is a negative number, because the volume of the snowball will decrease as the time pasese by.

(b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.

\frac{dr(t)}{dt}  = B*\sqrt{r(t)}

Here again appears a constant B for the "proportional" part. And i wrote the velocity as \frac{dr(t)}{dt} "the rate of change of the position with respect to te time".

7 0
3 years ago
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