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3 years ago

I need help with this

Mathematics

1 answer:

Nikitich [7]3 years ago

3 0

Answer: 1&3=29, 2&4=151

Step by Step:

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Julie spent 1/6 of her money on books , 1/3 of the remainder on a dress and saved the rest.

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The answers are 5/9 and $234.

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2 years ago

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a pattern has 14 triangles to every 18 yellow triangles. what is the ratio of yellow triangles to blue triangles?

erma4kov [3.2K]

9:7
Ratios are always simplified so by dividing both 18 and 14 by 2 you get 9 and seven. Because yellow triangles is stated first the 9 is put before the 7 blue triangles.

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A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

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3 years ago

Solve this Equation 6 = ___ - (-8)

Tcecarenko [31]

Answer:

-2

Step-by-step explanation:

____ is x

Move the terms.

6=x+8

-x=8-6

Calculate

-x=2

Change the signs

x= -2

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2 years ago

Which is the correct graph of y=2/x^2-4 ?

Elis [28]

The correct graph would be the first one

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2 years ago